A meter stick (a uniform thin rod of length 1.0 m and mass 0.30 kg) is placed on a fulcrum at the 61 cm mark, about which the meter stick can pivot. At what position (measured from the 0 cm end of the meter stick) should a 0.33 kg mass be hung to balance the system? Give your answer in cm, rounded to the nearest cm.
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- A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 3.74 g coins stacked over the 26.6 cm mark, the stick is found to balance at the 45.8 cm mark. What is the mass of the meter stick?The figure shows a set of blocks, each with identified masses. Estimate where a pivot should be placed beneath the lowest block so that the system would balance in equilibrium. 1.5 m 6 kg 5 kg 2 kg 2 m O 0-- 0.5 m 0.5 -- 1 m O 1-- 1.5 m O 1.5 -- 2 mA meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 3.29 g coins stacked over the 35.8 cm mark, the stick is found to balance at the 47.6 cm mark. What is the mass of the meter stick?
- A 1 kg ball is hung at the end of a rod 1 m long. If the system balances at a point on the rod 0.25 m from the end holding the mass, what is the mass of the rod?A meter stick has a mass of 0.18 kg and balances at its center. When a small chain is suspended from one end, the balance point moves 19.0 cm toward the end with the chain. Determine the mass of the chain.A meter stick (a uniform thin rod of length 1.0 m and mass 0.39 kg) is placed on a fulcrum at the 54 cm mark, about which the meter stick can pivot. At what position (measured from the 0 cm end of the meter stick) should a 0.22 kg mass be hung to balance the system? Give your answer in cm, rounded to the nearest cm.
- The bones of the forearm (radius and ulna) are hinged to the humerus at the elbow. The biceps muscle connects to the bones of the forearm about 2.15 cm beyond the joint. Assume the forearm has a mass of 2.45 kg and a length of 0.465 m. When the humerus and the biceps are nearly vertical and the forearm is horizontal, if a person wishes to hold an object of mass 5.35 kg so that her forearm remains motionless, what is the force F exerted by the biceps muscle? F=?17. A 0.25 kg meterstick has a 2kg mass suspended from the 80 cm mark and a 0.5 kg mass suspended from the 5 cm mark. At what mark should a pivot be placed to perfectly balance the meterstick? Answer 17:A torque of 20 N.m is applied to a solid, uniform hollow sphere of radius 0.50 m. If the hollow sphere accelerates at 1.5 rad/s2, what is the mass of the sphere?
- To get up on the roof, a person (mass 70.0 kg) places a 6.00 m aluminum ladder (mass 10.0 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. The ladder rests against the plastic rain gutter which we can assume to be frictionless. The center of mass of the ladder is 2.00 m from the bottom. The person is standing 3.00 m from the bottom. What are the magnitudes of the forces on the ladder at the top and bottom?Two children of mass 25 kg and 26 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the children are separated by a distance of 3.0 m, at what distance, in meters, from the pivot point is the smaller child sitting in order to maintain the balance?A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 58.0-gram mass is attached at the 22.5-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick?