When answering this problem, report the answer with the appropriate number of significant figures. When entering units, use proper abbreviated units with proper capitalization.A linear fit of the data in the chart yields the equation y = -5017x+19.081 with an R2 value of 0.9922. Determine the enthalpy (ΔH, in kJ) associated with dissolving KNO3.please put the answer in this format: ______x10 ____power ____units **Title: Thermodynamic Data for Solubility of KNO₃****Graph Description:**This graph presents the thermodynamic data for the solubility of potassium nitrate (KNO₃). The data is represented as a plot of the natural logarithm of the solubility product constant (ln Ksp) versus the inverse of temperature (1/T in K⁻¹).**Axes:**- The x-axis represents the inverse temperature, labeled as \(1/T\) (K⁻¹), ranging from approximately 0.003 to 0.00335.- The y-axis represents the natural logarithm of the solubility product constant, labeled as \( \text{ln Ksp} \), ranging from 0 to 4.**Data Trend:**- The data points show a downward linear trend, indicating that as the inverse temperature increases, the ln Ksp decreases. This suggests a decrease in solubility with decreasing temperature.**Line of Best Fit:**- The graph includes a dashed line representing the line of best fit. The equation for this line is given as \( y = -5017x + 19.081 \).- The correlation coefficient \( R^2 = 0.9922 \) suggests a very strong linear relationship between ln Ksp and 1/T.This graph is useful for understanding the temperature dependence of the solubility of KNO₃ and for calculating thermodynamic parameters related to its dissolution.

Answered: When answering this problem, report the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

When answering this problem, report the answer with the appropriate number of significant figures. When entering units, use proper abbreviated units with proper capitalization.

A linear fit of the data in the chart yields the equation y = -5017x+19.081 with an R2 value of 0.9922. Determine the enthalpy (ΔH, in kJ) associated with dissolving KNO₃.

please put the answer in this format: ______x10 ^____^power ____units

**Title: Thermodynamic Data for Solubility of KNO₃**

**Graph Description:**

This graph presents the thermodynamic data for the solubility of potassium nitrate (KNO₃). The data is represented as a plot of the natural logarithm of the solubility product constant (ln Ksp) versus the inverse of temperature (1/T in K⁻¹).

**Axes:**

- The x-axis represents the inverse temperature, labeled as \(1/T\) (K⁻¹), ranging from approximately 0.003 to 0.00335.
- The y-axis represents the natural logarithm of the solubility product constant, labeled as \( \text{ln Ksp} \), ranging from 0 to 4.

**Data Trend:**

- The data points show a downward linear trend, indicating that as the inverse temperature increases, the ln Ksp decreases. This suggests a decrease in solubility with decreasing temperature.

**Line of Best Fit:**

- The graph includes a dashed line representing the line of best fit. The equation for this line is given as \( y = -5017x + 19.081 \).
- The correlation coefficient \( R^2 = 0.9922 \) suggests a very strong linear relationship between ln Ksp and 1/T.

This graph is useful for understanding the temperature dependence of the solubility of KNO₃ and for calculating thermodynamic parameters related to its dissolution.

Expert Solution

Introduction

From the plot ln K_sp Vs 1/T

slope = ΔH / R
therefore ΔH = slope x 8.314 J/mol K

Equation for the line is,
y = -5017x+19.081
this is in the format
y = mx + C
where m is the slope

so, slope = -5017 K^-1

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions