Using (a) the ideal gas law and (b) the van der Waals equation, calculate the pressure exerted by 44.83 g of methaIn a 3.872-L vessel at 22.00 °C.For methane, a = 2.253 atm L2 mol2 and b = 4.278x10 2 L mol.Ideal gas law:atmVan der Waals:atmDo attractive or repulsive forces dominate?Retry tintire Groupmore group attermpts remainingSubmit Answer Two 1-L beakers, A and B, each containing a different aqueous solution of maltose (a nonvolatile sugar with MW =342.30 g/mol) are placed together in a box, which is then sealed. The temperature remalns constant at 20 °C. Initially,there is 760 mL of solution in A and 130 mL of solution in B. As the solutions stand in the sealed box, their volumeschange slowly for a whlle. When they stop changing, beaker A contalns 470 ml and beaker B contains 420 mL. It isthen determined that the solution in A is 0.530 M in maltose and has a density of 1.07 g mL!.(a) What is the molar concentration of maltose in the solution in beaker B at the end?M.(b) Calculate the concentration of maltose in the solution in A at the start.M.M.(c) Calculate the concentration of the maltose in the solution in B at the start.(d) The vapor pressure of pure water at 20 °C is 17.5 torr.What is the pressure of water vapor in the box at the end, after the volumes have stopped changing?torSubmit AnswerRetry Entire Group9 more group attempts remaining

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Using (a) the ideal gas law and (b) the van der Waals equation, calculate the pressure exerted by 44.83 g of methane In a 3.872-L vessel at 22.00 °C. For methane, a = 2.253 atm L2 mol? and b 4.278x102 L mol. Ideal gas law: atm Van der Waals: atm Do attractive or repulsive forces dominate?

Using (a) the ideal gas law and (b) the van der Waals equation, calculate the pressure exerted by 44.83 g of methane In a 3.872-L vessel at 22.00 °C. For methane, a = 2.253 atm L2 mol? and b 4.278x102 L mol. Ideal gas law: atm Van der Waals: atm Do attractive or repulsive forces dominate?

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Using (a) the ideal gas law and (b) the van der Waals equation, calculate the pressure exerted by 44.83 g of metha
In a 3.872-L vessel at 22.00 °C.
For methane, a = 2.253 atm L2 mol2 and b = 4.278x10 2 L mol.
Ideal gas law:
atm
Van der Waals:
atm
Do attractive or repulsive forces dominate?
Retry tintire Group
more group attermpts remaining
Submit Answer

Two 1-L beakers, A and B, each containing a different aqueous solution of maltose (a nonvolatile sugar with MW =
342.30 g/mol) are placed together in a box, which is then sealed. The temperature remalns constant at 20 °C. Initially,
there is 760 mL of solution in A and 130 mL of solution in B. As the solutions stand in the sealed box, their volumes
change slowly for a whlle. When they stop changing, beaker A contalns 470 ml and beaker B contains 420 mL. It is
then determined that the solution in A is 0.530 M in maltose and has a density of 1.07 g mL!.
(a) What is the molar concentration of maltose in the solution in beaker B at the end?
M.
(b) Calculate the concentration of maltose in the solution in A at the start.
M.
M.
(c) Calculate the concentration of the maltose in the solution in B at the start.
(d) The vapor pressure of pure water at 20 °C is 17.5 torr.
What is the pressure of water vapor in the box at the end, after the volumes have stopped changing?
tor
Submit Answer
Retry Entire Group
9 more group attempts remaining

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