Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
whats the 2.303 for
![» tye
t2 = 20.9 Hns
typ =
0.693/K
k =
0•693
0.603/ 20.9
K
= 0. 033 hit"
%3D
k = 3.3 X/0-2 hri!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8084e0e-ff04-4ae8-ba19-f863d28088fa%2Fbe559f7f-9f0e-4944-bd20-92a561ea65c5%2Fxmkecxt_processed.png&w=3840&q=75)
Transcribed Image Text:» tye
t2 = 20.9 Hns
typ =
0.693/K
k =
0•693
0.603/ 20.9
K
= 0. 033 hit"
%3D
k = 3.3 X/0-2 hri!
![Step 2
t2 = 20.9 Hns
ty2 = 0.603/K
k =
0•693
%3D
= 0:603/20-9
0.693
K
= 0: 033 hit
%3D
k = 3.3 X10-2 hr
r!
") t =
2.30 3
%3D
てime](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8084e0e-ff04-4ae8-ba19-f863d28088fa%2Fbe559f7f-9f0e-4944-bd20-92a561ea65c5%2Fgvifw4h_processed.png&w=3840&q=75)
Transcribed Image Text:Step 2
t2 = 20.9 Hns
ty2 = 0.603/K
k =
0•693
%3D
= 0:603/20-9
0.693
K
= 0: 033 hit
%3D
k = 3.3 X10-2 hr
r!
") t =
2.30 3
%3D
てime
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