whats the 2.303 for » tyet2 = 20.9 Hnstyp =0.693/Kk =0•6930.603/ 20.9K= 0. 033 hit"%3Dk = 3.3 X/0-2 hri! Step 2t2 = 20.9 Hnsty2 = 0.603/Kk =0•693%3D= 0:603/20-90.693K= 0: 033 hit%3Dk = 3.3 X10-2 hrr!") t =2.30 3%3Dてime

Given that t=(2.303/k)log [A0/At] Where 2.303 is a constant.

Answered: whats the 2.303 for

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whats the 2.303 for

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

whats the 2.303 for

» tye
t2 = 20.9 Hns
typ =
0.693/K
k =
0•693
0.603/ 20.9
K
= 0. 033 hit"
%3D
k = 3.3 X/0-2 hri!

Step 2
t2 = 20.9 Hns
ty2 = 0.603/K
k =
0•693
%3D
= 0:603/20-9
0.693
K
= 0: 033 hit
%3D
k = 3.3 X10-2 hr
r!
") t =
2.30 3
%3D
てime

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