Assignment 4.docx - Word Equation Tools Lorelei Chavez Home Insert Design Layout References Mailings Review View Help Design O Tell me what you want to do Cambria Math -12 A A Aa - 三,三,, イ AaBbCcDc AaBbCcDc AaBbC AaBbCcD AaB AaBbCcC AaBbccD AaBbCcD AaBbCcDr AaBbCcDr BIU abe X, x A- at- A - 三 前,,。 TNormal 1 No Spac. Heading 1 Heading 2 Subtle Em. Emphasis Intense E.. Format Painter Title Subtitle Strong Clipboard Font Paragraph Styles 8.38. A gas sample has a pressure of 2.35 atm when the temperature is -15 C. What is the final pressure, in atmospheres, when the temperature is 46 C, with no change in the volume or amount of gas? 309 PM A o de Page 3 of 3 921 words 2 Type here to search DELL
Assignment 4.docx - Word Equation Tools Lorelei Chavez Home Insert Design Layout References Mailings Review View Help Design O Tell me what you want to do Cambria Math -12 A A Aa - 三,三,, イ AaBbCcDc AaBbCcDc AaBbC AaBbCcD AaB AaBbCcC AaBbccD AaBbCcD AaBbCcDr AaBbCcDr BIU abe X, x A- at- A - 三 前,,。 TNormal 1 No Spac. Heading 1 Heading 2 Subtle Em. Emphasis Intense E.. Format Painter Title Subtitle Strong Clipboard Font Paragraph Styles 8.38. A gas sample has a pressure of 2.35 atm when the temperature is -15 C. What is the final pressure, in atmospheres, when the temperature is 46 C, with no change in the volume or amount of gas? 309 PM A o de Page 3 of 3 921 words 2 Type here to search DELL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Expert Solution
Step 1 Introduction
Principle:
The ideal gas equation is PV=nRT.
where P-Pressure of the gas
V-Volume of the gas
n-amount of the gas
T-Temperature of the gas
R-Gas constant
P.S.: All the Temperature should be in Kelvin for the calculations
In the given problem, the volume of the gas(V) and the amount of the gas(n) are constant. Thus, they are taken as constant.
Given:
Initial Pressure(P1) = 2.35 atm
Initial Temperature(T1) = -15 = -15+273K = 258K
Final Temperature(T2) = 46 = 46+273 = 319K
To Find:
Final Pressure(P2)
Step by step
Solved in 3 steps
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