6. Mass of water (2- 1) 102a lousg-4.28g=101.99g %3D 7. Temperature change (4- 3) -20.1°C oC 2.9°C-23.o°C%=D20.1°C 8. Joules lost by water (Show calculations.) 9. Joules needed to melt ice = joules lost by water (8) 26.21g-8 10. Mass of ice that melted (5- 2) (Show calculations.) 132.1-106.25-26.24 1oL6.253=20.24 J/g 1. Heat of fusion (joules to melt 1 g of ice) (Show calculations.)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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I'm not sure that the calculation of the negative number is correct. Also want to be sure I'm doing all calculations correctly.
41.4
C. Heat of Fusion
4.28g
104.25a
23.0°2
1. Mass of calorimeter
2. Mass of calorimeter + water
3. Initial water temperature
°C
4. Final water temperature (ice added)
2.9°C
°C
132.49a
5. Mass of calorimeter + water + melted ice
Transcribed Image Text:41.4 C. Heat of Fusion 4.28g 104.25a 23.0°2 1. Mass of calorimeter 2. Mass of calorimeter + water 3. Initial water temperature °C 4. Final water temperature (ice added) 2.9°C °C 132.49a 5. Mass of calorimeter + water + melted ice
th Gen
ins
ctrl
(intel
Energy and Matter
59
Calculations
6. Mass of water (2 – 1)
g
lo625g-4.28g=101.975
%3D
7. Temperature change (4 – 3)
-20.1°C °C
2.9°C-23.0°C= 20.1°C
8. Joules lost by water
J
(Show calculations.)
9. Joules needed to melt ice = joules lost by water (8)
J
10. Mass of ice that melted (5 – 2)
(Show calculations.)
J/g
11. Heat of fusion (joules to melt 1 g of ice)
(Show calculations.)
erstions and Problems
Transcribed Image Text:th Gen ins ctrl (intel Energy and Matter 59 Calculations 6. Mass of water (2 – 1) g lo625g-4.28g=101.975 %3D 7. Temperature change (4 – 3) -20.1°C °C 2.9°C-23.0°C= 20.1°C 8. Joules lost by water J (Show calculations.) 9. Joules needed to melt ice = joules lost by water (8) J 10. Mass of ice that melted (5 – 2) (Show calculations.) J/g 11. Heat of fusion (joules to melt 1 g of ice) (Show calculations.) erstions and Problems
Expert Solution
Step 1

Joules lost by water = Mass of water ×temperature change×Specific heat capacity

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