Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![**Question 4:**
How many mmoles of SCN⁻ ion are there in 1.0 mL of 0.00200 M KSCN?
**Explanation:**
To solve this, you'll need to use the formula for calculating millimoles (mmoles):
\[
\text{mmoles} = \text{Molarity (M)} \times \text{Volume (mL)}
\]
Given:
- Molarity of KSCN = 0.00200 M
- Volume = 1.0 mL
Plug the values into the formula:
\[
\text{mmoles} = 0.00200 \, \text{M} \times 1.0 \, \text{mL} = 0.00200 \, \text{mmoles}
\]
Therefore, there are 0.00200 mmoles of SCN⁻ ion in 1.0 mL of a 0.00200 M KSCN solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b6b6912-3084-4759-aee0-bc0c3c3b661a%2F4528a764-0816-46a8-83fb-614de8c6c229%2Fgfrhbg6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 4:**
How many mmoles of SCN⁻ ion are there in 1.0 mL of 0.00200 M KSCN?
**Explanation:**
To solve this, you'll need to use the formula for calculating millimoles (mmoles):
\[
\text{mmoles} = \text{Molarity (M)} \times \text{Volume (mL)}
\]
Given:
- Molarity of KSCN = 0.00200 M
- Volume = 1.0 mL
Plug the values into the formula:
\[
\text{mmoles} = 0.00200 \, \text{M} \times 1.0 \, \text{mL} = 0.00200 \, \text{mmoles}
\]
Therefore, there are 0.00200 mmoles of SCN⁻ ion in 1.0 mL of a 0.00200 M KSCN solution.
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