What is wrong with the following code snippet? void myfun (char* p) { } *P = toupper (*p); int main() { } string myword = "YouHadMeAtHello"; for (int i = 0; i<10; i++) { myfun (myword [i]); } cout << myword << endl; return 0; Must use c_str() to access individual characters of the string variable myword Array indices are out of bounds Must use atoi () to convert integers to characters The toupper() function cannot be applied to a single character

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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### Code Error Analysis

#### Code Snippet:
```cpp
void myfun(char* p)
{
    *p = toupper(*p);
}

int main()
{
    string myword = "YouHadMeAtHello";
    for (int i = 0; i < 10; i++)
    {
        myfun(myword[i]);
    }
    cout << myword << endl;
    return 0;
}
```

#### Problem Statement:
What is wrong with the following code snippet?

#### Options:
- ○ Must use `c_str()` to access individual characters of the string variable `myword`
- ○ Array indices are out of bounds
- ○ Must use `atoi()` to convert integers to characters
- ○ The `toupper()` function cannot be applied to a single character

#### Analysis:
- The code attempts to convert the first 10 characters of the string `myword` to uppercase using the `myfun` function.
- The function `myfun` is intended to take a pointer to a character and convert it to uppercase using `toupper`.
- In the `main` function, `myfun` is called with `myword[i]`, which is a character, not a pointer.
- Passing `myword[i]` by reference would resolve this issue. 

#### Correct Explanation:
The array indices are not out of bounds, as the code accesses the first 10 characters. The correct option should indicate that `myfun(myword[i])` does not pass a pointer.

#### Suggestion for Correction:
Change the function call to pass the address of the character:
```cpp
myfun(&myword[i]);
```

This ensures the character element is treated as a pointer when passed to `myfun`.
Transcribed Image Text:### Code Error Analysis #### Code Snippet: ```cpp void myfun(char* p) { *p = toupper(*p); } int main() { string myword = "YouHadMeAtHello"; for (int i = 0; i < 10; i++) { myfun(myword[i]); } cout << myword << endl; return 0; } ``` #### Problem Statement: What is wrong with the following code snippet? #### Options: - ○ Must use `c_str()` to access individual characters of the string variable `myword` - ○ Array indices are out of bounds - ○ Must use `atoi()` to convert integers to characters - ○ The `toupper()` function cannot be applied to a single character #### Analysis: - The code attempts to convert the first 10 characters of the string `myword` to uppercase using the `myfun` function. - The function `myfun` is intended to take a pointer to a character and convert it to uppercase using `toupper`. - In the `main` function, `myfun` is called with `myword[i]`, which is a character, not a pointer. - Passing `myword[i]` by reference would resolve this issue. #### Correct Explanation: The array indices are not out of bounds, as the code accesses the first 10 characters. The correct option should indicate that `myfun(myword[i])` does not pass a pointer. #### Suggestion for Correction: Change the function call to pass the address of the character: ```cpp myfun(&myword[i]); ``` This ensures the character element is treated as a pointer when passed to `myfun`.
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