What is the time complexity of these [ Sum += y is a short form notation for Sum = Sum + y.] for (int i = 1 to n) { for (int j = i to n) { for (int k = j to n) { Sum + a[i]*b[j]*c[k] 1) { } } If (gcd(i, j) j = n } == j = 1 while (j

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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What is
the
time
complexity of these
[Sum += y is a short form notation for Sum= Sum + y.]
for (int i = 1 to n) {
for (int j = i to n) {
for (int k = j to n) {
Sum + a[i]*b[j]*c[k]
1) {
}
If (gcd(i, j)
j = n
}
}
==
j = 1
while (j<n) {
k = j
while (k <n) {
}
}
U.W
algorithms,
Sum + a[k]*b[k]
k + k
+= 0.25 * n
int j = 2
while (j<n) {
int k = j
while (k <n) {
Sum + a[k]*b[k]
k+= n¹/3 log n
}
in terms of
Min
j = j*sqrt(5)
n?
Transcribed Image Text:What is the time complexity of these [Sum += y is a short form notation for Sum= Sum + y.] for (int i = 1 to n) { for (int j = i to n) { for (int k = j to n) { Sum + a[i]*b[j]*c[k] 1) { } If (gcd(i, j) j = n } } == j = 1 while (j<n) { k = j while (k <n) { } } U.W algorithms, Sum + a[k]*b[k] k + k += 0.25 * n int j = 2 while (j<n) { int k = j while (k <n) { Sum + a[k]*b[k] k+= n¹/3 log n } in terms of Min j = j*sqrt(5) n?
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