What is the time complexity of these [ Sum += y is a short form notation for Sum = Sum + y.] for (int i = 1 to n) { for (int j = i to n) { for (int k = j to n) { Sum + a[i]*b[j]*c[k] 1) { } } If (gcd(i, j) j = n } == j = 1 while (j
What is the time complexity of these [ Sum += y is a short form notation for Sum = Sum + y.] for (int i = 1 to n) { for (int j = i to n) { for (int k = j to n) { Sum + a[i]*b[j]*c[k] 1) { } } If (gcd(i, j) j = n } == j = 1 while (j
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![What is
the
time
complexity of these
[Sum += y is a short form notation for Sum= Sum + y.]
for (int i = 1 to n) {
for (int j = i to n) {
for (int k = j to n) {
Sum + a[i]*b[j]*c[k]
1) {
}
If (gcd(i, j)
j = n
}
}
==
j = 1
while (j<n) {
k = j
while (k <n) {
}
}
U.W
algorithms,
Sum + a[k]*b[k]
k + k
+= 0.25 * n
int j = 2
while (j<n) {
int k = j
while (k <n) {
Sum + a[k]*b[k]
k+= n¹/3 log n
}
in terms of
Min
j = j*sqrt(5)
n?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9d62a21-9464-485d-a661-cdb5131d30ee%2F13bfe41a-542d-45fc-a531-fe71f35ee4a1%2F5hh2k5v_processed.png&w=3840&q=75)
Transcribed Image Text:What is
the
time
complexity of these
[Sum += y is a short form notation for Sum= Sum + y.]
for (int i = 1 to n) {
for (int j = i to n) {
for (int k = j to n) {
Sum + a[i]*b[j]*c[k]
1) {
}
If (gcd(i, j)
j = n
}
}
==
j = 1
while (j<n) {
k = j
while (k <n) {
}
}
U.W
algorithms,
Sum + a[k]*b[k]
k + k
+= 0.25 * n
int j = 2
while (j<n) {
int k = j
while (k <n) {
Sum + a[k]*b[k]
k+= n¹/3 log n
}
in terms of
Min
j = j*sqrt(5)
n?
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