1. What is the slope of Car One (numerical answer)? Show work.2. When does Car Two catch Car One? How far do they travel in that time?3. What is the shape of Car Two’s slope? Why? x (m)12080-400Constant velocity vs. constant accelerationPosition vs. time-40-0 2 4 6 8 10 12 14 16 18 20-30 -20 -10 0 10 20 30 40 50 60 70 80 90t-20.00 sx-100.00 mx= 100.00 mPlay PauseConstant velocity: Car 1 (red), initial valuesPosition: -30 m+30 mVelocity: 0 m/s<< StepAcceleration: 0.0 m/s/s-0Step >>0.5Graph: Position vs. timev-5.00 m/sy=10.00 m/sReset5Constant acceleration: Car 2 (blue)2 m/s/st(s)10 m/sVelocity vs. time→x (m)100This work by Andrew Duffy is licensed under a Creative CommonsAttribution-NonCommercial-ShareAlike 4.0 International License.This simulation can be found in the collection athttp://physics.bu.edu/~duffy/classroom.html.The counter has been running on this page since 8-9-2018. Thenumber of people accessing the page since then is:057554

Slope of car one: slope=velocity=v=xfinal-xinitialtfinal-tinitial we can take the boundary…

Answered: What is the slope of Car One (numerical…

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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1. What is the slope of Car One (numerical answer)? Show work. 2. When does Car Two catch Car One? How far do they travel in that time? 3. What is the shape of Car Two’s slope? Why?

x (m)
120
80-
40
0
Constant velocity vs. constant acceleration
Position vs. time
-40-
0 2 4 6 8 10 12 14 16 18 20
-30 -20 -10 0 10 20 30 40 50 60 70 80 90
t-20.00 s
x-100.00 m
x= 100.00 m
Play Pause
Constant velocity: Car 1 (red), initial values
Position: -30 m
+30 m
Velocity: 0 m/s
<< Step
Acceleration: 0.0 m/s/s-
0
Step >>
0.5
Graph: Position vs. time
v-5.00 m/s
y=10.00 m/s
Reset
5
Constant acceleration: Car 2 (blue)
2 m/s/s
t(s)
10 m/s
Velocity vs. time
→x (m)
100
This work by Andrew Duffy is licensed under a Creative Commons
Attribution-NonCommercial-ShareAlike 4.0 International License.
This simulation can be found in the collection at
http://physics.bu.edu/~duffy/classroom.html.
The counter has been running on this page since 8-9-2018. The
number of people accessing the page since then is:
057554

Expert Solution

Step 1

Slope of car one:

$s l o p e = v e l o c i t y = v = \frac{x_{f i n a l} - x_{i n i t i a l}}{t_{f i n a l} - t_{i n i t i a l}} w e c a n t a k e t h e b o u n d a r y p o i n t s t o f i n d t h e s l o p e b e c a u s e t h e l i n e i s s t r a i g h t o r t h e s l o p e i s s a m e e v e r y w h e r e : t h e n v = \frac{100 - 0}{20 - 0} = 5 m / s$

From the graph its clear that both the cars are at same position when

t=20s

and both cars have travelled a distance from graph in 20s

x=100 m

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