14. If a man ran at constant 4 m/s for 40 s and then he ran at 8 m/s back to his starting position. Insert below a screenshot of your worksheet which shows how you obtain final answer for each question a. What was the total time of his run? b. What would be the total distance he covered? c. What would be his average speed? m/s d. What was his displacement at the end of his trip? e. What was his average velocity? m/s and direction (if any)

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Chapter1: Units, Trigonometry. And Vectors
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### Problem 14

If a man runs at a constant speed of 4 m/s for 40 seconds and then he runs back at 8 m/s to his starting position:

**Diagram Explanation:**
- Distance (d) with a speed of 4 m/s over time \( t_1 = 40 \, \text{sec} \)
- Returns at 8 m/s over time \( t_2 = \text{calculated} \)

**Calculations:**

1. **Distance Calculation:**
   - Speed × Time = Distance
   - \( d = 4 \times 40 = 160 \, \text{m} \)

2. **Going Back:**
   - \( 160 \, \text{m} = 8 \times t_2 \)
   - \( t_2 = 20 \, \text{seconds} \)

3. **Total Time:**
   - \( 40 + 20 = 60 \, \text{seconds} \)

4. **Total Distance:**
   - \( \text{Total distance} = d + d = 2(160) = 320 \, \text{m} \)

5. **Average Speed:**
   - \(\text{Average speed} = \frac{\text{distance}}{\text{time}} = \frac{320}{60 \, \text{sec}} = \frac{16}{3} \, \text{m/s}\)

6. **Displacement:**
   - Defined as the minimum distance between initial and final positions.
   - \( s = 0 \, \text{m} \)

7. **Average Velocity:**
   - \(\text{Average velocity} = \frac{\text{displacement}}{\text{time}} = \frac{0 \, \text{m}}{60 \, \text{sec}} = 0 \, \text{m/s}\)

**Note:** The direction cannot be defined as the displacement is zero.
Transcribed Image Text:### Problem 14 If a man runs at a constant speed of 4 m/s for 40 seconds and then he runs back at 8 m/s to his starting position: **Diagram Explanation:** - Distance (d) with a speed of 4 m/s over time \( t_1 = 40 \, \text{sec} \) - Returns at 8 m/s over time \( t_2 = \text{calculated} \) **Calculations:** 1. **Distance Calculation:** - Speed × Time = Distance - \( d = 4 \times 40 = 160 \, \text{m} \) 2. **Going Back:** - \( 160 \, \text{m} = 8 \times t_2 \) - \( t_2 = 20 \, \text{seconds} \) 3. **Total Time:** - \( 40 + 20 = 60 \, \text{seconds} \) 4. **Total Distance:** - \( \text{Total distance} = d + d = 2(160) = 320 \, \text{m} \) 5. **Average Speed:** - \(\text{Average speed} = \frac{\text{distance}}{\text{time}} = \frac{320}{60 \, \text{sec}} = \frac{16}{3} \, \text{m/s}\) 6. **Displacement:** - Defined as the minimum distance between initial and final positions. - \( s = 0 \, \text{m} \) 7. **Average Velocity:** - \(\text{Average velocity} = \frac{\text{displacement}}{\text{time}} = \frac{0 \, \text{m}}{60 \, \text{sec}} = 0 \, \text{m/s}\) **Note:** The direction cannot be defined as the displacement is zero.
**Problem Statement:**

14. If a man ran at a constant 4 m/s for 40 s and then he ran at 8 m/s back to his starting position.

*Insert below a screenshot of your worksheet which shows how you obtain the final answer for each question.*

a. What was the total time of his run? _______ s

b. What would be the total distance he covered? _______ m

c. What would be his average speed? _______ m/s

d. What was his displacement at the end of his trip? _______ m

e. What was his average velocity? _______ m/s and direction (if any) _______
Transcribed Image Text:**Problem Statement:** 14. If a man ran at a constant 4 m/s for 40 s and then he ran at 8 m/s back to his starting position. *Insert below a screenshot of your worksheet which shows how you obtain the final answer for each question.* a. What was the total time of his run? _______ s b. What would be the total distance he covered? _______ m c. What would be his average speed? _______ m/s d. What was his displacement at the end of his trip? _______ m e. What was his average velocity? _______ m/s and direction (if any) _______
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