What is the size of the effective sending window if the following information is collected in the sending TCP: Sending buffer size = 32000 Byte Last Byte Acknowledged (LBA) = 22555 Last Byte Sent (LBS) = 33666 Advertised Window = 15000 Byte Congestion Window (cwnd) = 12000 Byte O1. 32000 O I. 12000 O II. 15000 O V. 889 If two hosts start communicating using TCP Reno (with fast retransmit and fast recovery). What would be the size of the congestion window after the 10th RTT (the window that will be used in the 11th RTT) if the congestion threshold is initially set to 16 MSS and if 3 duplicate acknowledgments have been observed during the 7th RTT. O1. 8 O I. 22 O II. 12 O V. 512 What is the maximum advertised window size if the following information is collected about the receiver buffer: Buffer size = 12000 bytes Next Byte Expected (NBE) = 555 Last Byte Read by the application process (LBR) = 222 No out of sequence data received O1. 222 O II. 12000 O II. 555 O V. 11668

What is the size of the effective sending window if the following information is collected in the sending TCP: Sending buffer size = 32000 Byte Last Byte Acknowledged (LBA) = 22555 Last Byte Sent (LBS) = 33666 Advertised Window = 15000 Byte Congestion Window (cwnd) = 12000 Byte O1. 32000 O I. 12000 O II. 15000 O V. 889 If two hosts start communicating using TCP Reno (with fast retransmit and fast recovery). What would be the size of the congestion window after the 10th RTT (the window that will be used in the 11th RTT) if the congestion threshold is initially set to 16 MSS and if 3 duplicate acknowledgments have been observed during the 7th RTT. O1. 8 O I. 22 O II. 12 O V. 512 What is the maximum advertised window size if the following information is collected about the receiver buffer: Buffer size = 12000 bytes Next Byte Expected (NBE) = 555 Last Byte Read by the application process (LBR) = 222 No out of sequence data received O1. 222 O II. 12000 O II. 555 O V. 11668

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

IP datagrams on a specific network can carry a maximum of only 440 bytes in the data portion. A node on this network, running an application using TCP generates a TCP segment with 1,900 bytes in the data portion. How many IP packets are transmitted to carry this TCP segment, and what are their sizes (including the header of 20 bytes)?
What happens if one of the TCP peers fails to publish its Maximum segment size MSS value during the handshake?
Suppose the sequence number field on a TCP packet is 46005. The packet carries 102 bytes of (application-layer) data. The TCP header size on this packet is 20 bytes. (a) What is the sequence number of the last application byte contained in the packet above? (b) What is the value of the acknowledgment number field on the ACK that the receiver generates for the packet above? (c) Do you have sufficient information in this question to determine the value of the sequence number field of the ACK packet that the receiver generates for the packet above? If so, what is the sequence number? If not, why not? (d) If the size of the TCP header were larger (e.g., 24 bytes, due to additional TCP options), would your answers to parts (a)–(c) change? Why or why not?
When using HTTP streaming, are the TCP receive buffer and the client's application buffer the same thing as each other? If they don't communicate with one another, how do they interact with one another?
Computer Science In Python, I am trying to make a client and server code that passes the payload with the requirements. The client has to specify the length of the data packet, up to max, specify how many times to pass the data packet, and specify the server IPv4 address. Both the client and the server need timer functions and compute the time needed to perform the number of sends both the Client and the server need to display the local and remote IPv4 addresses, total time, and bytes per second. Please help, Thanks.
39. The figure below shows the TCP Congestion Window for various transmission rounds of a TCP connection. 20 18 16 14 12 10 4 2 2 4 6 10 12 14 16 18 20 Transmission Round How many more (or less) segments will TCP Tahoe send compared to TCP Reno between the transmission rounds 12 and 16 inclusive (i.e., t12 to t16) for the same sequence of events as shown in the graph above (i.e., loss events at t11, tl4 and t16)? a. TCP Tahoe send 13 less segments compared to TCP Reno b. TCP Tahoe send 20 more segments compared to TCP Reno c. TCP Tahoe send 13 more segments compared to TCP Reno d. TCP Tahoe send 20 less segments compared to TCP Reno e. TCP Tahoe send 28 less segments compared to TCP Reno Congestion Window (MSS) 00
Consider a long-lived TCP session with an end- to-end bandwidth of 1 Gbps (= 10⁹ bits-per- second). The session starts with a sequence number of 1234. The minimum time (in seconds, rounded to the closest integer) before this sequence number can be used again is
13. The following figures plot the timeline for sending TCP segments by host A and TCP ACKS by host B, where “seq #” is the value of the sequence number in the TCP header, and "ACK #” is the value of the acknowledge number in the TCP header. Assume that every segment always includes 500 bytes of data, excluding the TCP header. A seg #: 1000 seq #: 1500 seq #: 2000 seq #: 2500 (1) B ACK #: a ACK #: b ACK #: c ACK #: d A seq #: 1000 seq #: 1500 seq #: 2000 seq #: 2500 (2) B ACK #: r ACK #: s TACK 1) In Figure (1), the second ACK sent out by host B gets lost in the network. a) What are the acknowledge numbers a, b, c, and d? b) Will sender A think the segment with seq#=1500 was lost because it never receives the acknowledgement from B containing ACK# = b? 2) In Figure (2), the second TCP segment from host A to host B gets delayed in the network but later arrives at B. What should be the value for the ACK number r, s and t?
In TCP connection, congestion occurs if the load on the network is greater than the capacity of the network. TCP uses the following algorithm to handle congestion. The algorithm is based on the size of the congestion window (cwnd) which starts with one maximum segment size (MSS). The MSS is determined during connection establishment. At each time the whole window of segments is acknowledged (one transmission), the size of the window grows exponentially. To stop this exponential growth, the sender keeps the track of a threshold. The threshold is set to 16 MSS. After reaching the threshold, the size of the congestion window is increased by 1. After how many transmissions the congestion window size will be 22 MSS?
Consider a long-lived TCP session with an end- to-end bandwidth 500 Mb/s. The session starts with a sequence number of 3465. The minimum time (in seconds) before this sequence number can be used again is
Computer Networks
Write the simplified version for the following IPv6 address:A700:401:0000:0000:71A0:0000:0000:04A1