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What is the rate law for the reaction and what is the numerical value of k?

What is the rate law for the reaction and what is the numerical value of k?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A reaction is performed to study the oxidation of arsenate ion by cerium(IV) ion in aqueous solution: + 2 Ce** + H20 AsO, + 2 Ce3+ + 2 H* The following reaction rate data was obtained in four separate experiments. [Ce**Jo• M [AsO3³ lo, M 3.60x10-2 7.20×10-2 3.60x10-2 7.20×x10-2 Experiment Initial Rate, Ms1 6.89x10-3 1.38×10-2 2.76x10-2 5.52x10-2 1 0.595 2 0.595 1.19 14 1.19 What is the rate law for the reaction and what is the numerical value of k? Complete the rate law in the box below. Remember that an exponent of 'l' is not shown and concentrations taken to the zero power do not appear. Rate = k = M2s!.
Transcribed Image Text:A reaction is performed to study the oxidation of arsenate ion by cerium(IV) ion in aqueous solution: + 2 Ce** + H20 AsO, + 2 Ce3+ + 2 H* The following reaction rate data was obtained in four separate experiments. [Ce**Jo• M [AsO3³ lo, M 3.60x10-2 7.20×10-2 3.60x10-2 7.20×x10-2 Experiment Initial Rate, Ms1 6.89x10-3 1.38×10-2 2.76x10-2 5.52x10-2 1 0.595 2 0.595 1.19 14 1.19 What is the rate law for the reaction and what is the numerical value of k? Complete the rate law in the box below. Remember that an exponent of 'l' is not shown and concentrations taken to the zero power do not appear. Rate = k = M2s!.
Expert Solution
Step 1

Let the rate equation is : rate = k[AsO3^3-]^x[Ce^4+]^y ....(1) 

From experiment 1, 6.89*10^-3 = k(3.6*10^-2)^x(0.595)^y  ...(2)

From experiment 2, 13.8*10^-3 = k(7.2*10^-2)^x(0.595)^y ....(3) 

Dividing 3 by 1, we have : 2 = 2^x or, x = 1. 

From experiment 3, 27.6*10^-3 = k(3.6*10^-2)^x(1.19)^y ....(4)

Dividing 4 by 2, we have : 4 = 2^2 = 2^x or, x = 2 

A. Hence, rate = k[AsO3^3-]^1[Ce^4+]^2 

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