1: For a certain reaction, Kc = 1.63×105 and kf= 2.79 M−2⋅s−1. Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction 2: For a different reaction, Kc = 1.53×104, kf=947s−1, and kr= 6.20×10−2 s−1 . Adding a catalyst increases the forward rate constant to 2.52×105 s−1. What is the new value of the reverse reaction constant, kr, after adding catalyst?
1: For a certain reaction, Kc = 1.63×105 and kf= 2.79 M−2⋅s−1. Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction 2: For a different reaction, Kc = 1.53×104, kf=947s−1, and kr= 6.20×10−2 s−1 . Adding a catalyst increases the forward rate constant to 2.52×105 s−1. What is the new value of the reverse reaction constant, kr, after adding catalyst?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1: For a certain reaction, Kc = 1.63×105 and kf= 2.79 M−2⋅s−1. Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction
2: For a different reaction, Kc = 1.53×104, kf=947s−1, and kr= 6.20×10−2 s−1 . Adding a catalyst increases the forward rate constant to 2.52×105 s−1. What is the new value of the reverse reaction constant, kr, after adding catalyst?
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