1: For a certain reaction, Kc = 1.63×105 and kf= 2.79 M−2⋅s−1. Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction 2: For a different reaction, Kc = 1.53×104, kf=947s−1, and kr= 6.20×10−2 s−1 . Adding a catalyst increases the forward rate constant to 2.52×105 s−1. What is the new value of the reverse reaction constant, kr, after adding catalyst?
1: For a certain reaction, Kc = 1.63×105 and kf= 2.79 M−2⋅s−1. Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction 2: For a different reaction, Kc = 1.53×104, kf=947s−1, and kr= 6.20×10−2 s−1 . Adding a catalyst increases the forward rate constant to 2.52×105 s−1. What is the new value of the reverse reaction constant, kr, after adding catalyst?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.35QE
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1: For a certain reaction, Kc = 1.63×105 and kf= 2.79 M−2⋅s−1. Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction
2: For a different reaction, Kc = 1.53×104, kf=947s−1, and kr= 6.20×10−2 s−1 . Adding a catalyst increases the forward rate constant to 2.52×105 s−1. What is the new value of the reverse reaction constant, kr, after adding catalyst?
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