What is the rate law for the following mechanism: 2 A+B2C (fast equilibrium; rate of forward reaction: k1. rate of reverse reaction: k.1) B+C -D (slow, rate: k2) D -E (fast, rate: k3) Rate= k2 (k1/k.1)[A]?{B] B. Rate= k2 [A]°[B]? Rate= k2 [B][C] D. Rate= (k1/k.1) [A][B]² O E. Rate= k2 (k1/k.1) [A]²{B]²

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Chapter1: Chemical Foundations
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What is the rate law for the following mechanism:
2 A+B2C (fast equilibrium; rate of forward reaction: k1: rate of reverse reaction: k.1)
В +с —D (slow, rate: k2)
D - E
(fast, rate: k3)
O A Rate= k2 (k1 k.1)[A]²B]
Rate= k2 [A]°[B]?
В.
Rate= k2 [B][C]
C.
Rate= (k1 /k.1) [A][B]²
D.
E.
Rate= k2 (k1 /k-1) [A]²[B]²
Transcribed Image Text:What is the rate law for the following mechanism: 2 A+B2C (fast equilibrium; rate of forward reaction: k1: rate of reverse reaction: k.1) В +с —D (slow, rate: k2) D - E (fast, rate: k3) O A Rate= k2 (k1 k.1)[A]²B] Rate= k2 [A]°[B]? В. Rate= k2 [B][C] C. Rate= (k1 /k.1) [A][B]² D. E. Rate= k2 (k1 /k-1) [A]²[B]²
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