Step 1 Step 2 The rate law is Rate - klA][B] Rate-k[C][D] Rate-k[A][D][E] Rate-k[A][D] Rate-k[A] A+B-C C+D+B+E Slow Fast

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
Step 2
The rate law is
Rate=kIA][B]
Rate= k[C][D]
Rate-k[A][D][E]'
Rate-k[A][D]
Rate-k[A]
A+B C
0.90atm
3.3 atm
1.8 atm
C+D+B+E
Slow
Fast
26. Starting with pure COF,, the system is allowed to reach equilibrium according to the equation below.
2 COF,(g) CO(g) + CF(g) K,- 2.2x 10° at 298 K
If the equilibrium pressure of COF, is 1.2 x 10 atm, what is the equilibrium pressure of CF,?
Transcribed Image Text:Step 1 Step 2 The rate law is Rate=kIA][B] Rate= k[C][D] Rate-k[A][D][E]' Rate-k[A][D] Rate-k[A] A+B C 0.90atm 3.3 atm 1.8 atm C+D+B+E Slow Fast 26. Starting with pure COF,, the system is allowed to reach equilibrium according to the equation below. 2 COF,(g) CO(g) + CF(g) K,- 2.2x 10° at 298 K If the equilibrium pressure of COF, is 1.2 x 10 atm, what is the equilibrium pressure of CF,?
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