What is the rate law for the following mechanism: 2A +B + C →D (slow, rate: kj) A+D 2E (fast equilibrium; rate of forward reaction: k2, rate of reverse reaction: k_2) E +G → H (fast, rate: k3)

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the rate law for the following mechanism:
2A +B + C →D (slow, rate: kj)
A+D 2E (fast equilibrium; rate of forward reaction: k2, rate of reverse reaction: k_2)
E +G → H
(fast, rate: k3)
Rate= k1 [A]?[B][C]
O A.
Rate= k1 (k2/k.2)[A][D]
O B.
Rate= k1 [A][D]
OC.
Rate= kl (k2/k_2) [A][B][C]
O E. Rate= k1 (k2/k_2) [A]²[B][C]
Transcribed Image Text:What is the rate law for the following mechanism: 2A +B + C →D (slow, rate: kj) A+D 2E (fast equilibrium; rate of forward reaction: k2, rate of reverse reaction: k_2) E +G → H (fast, rate: k3) Rate= k1 [A]?[B][C] O A. Rate= k1 (k2/k.2)[A][D] O B. Rate= k1 [A][D] OC. Rate= kl (k2/k_2) [A][B][C] O E. Rate= k1 (k2/k_2) [A]²[B][C]
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