I just need to know if all my work/calculations with this lab report are correct, thank you so much!

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 5ALQ: Consider the following statements: In general, the rate of a chemical reaction increases a bit at...
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I just need to know if all my work/calculations with this lab report are correct, thank you so much!
How measure the rate? I2 is yellow. Will measure how long
for it to react (lose its color).
So, Rate = A[l2]/Atime
Data and Calculations:
Table 1. Reactant Volumes & Reaction Times
Volume (ml) of:
Mixture
4.0 M
acetone
1.0 M
HCI
time (sec)
0.0050 M
H20
12
A
B
1.00
1.00
230
1.00
1.00
1.00
2.00
1.00
2.00
1.00
106
120
110
1.00
2.00
1.00
1.00
1.00
0.50
2.50
Table 2. Initial Concentrations & Rate of Reaction
Mixture
A
B
[acetone]
.80 M
[H*]
.20 M
[k]
.0010 M
Rate =A[la]/time
4.34 x 10-6
9.43 x 10 -6
1.6 M
.80M
•20M
0010M
.0010 4
0005M
8.33 x 10-6
4.54 x lo-G
.40M
D
• 80 M
- 20 M
The Dilution Factor Method:
Original V
(4M)(1 ml) = .8M
(5 ml)
Final Total V
Reactant Order Determination
Calculate the value of m (order with respect to acetone)
1.6
0.000009433
2= 2.17
Rates = k[ace]m[ÁT
Ratea = k[ace]™[H]
0.8
0.000004347
1.12
(2 decimals) m=,
(nearest whole number)
m =
Calculate the value of n (order with respect to the H*)
0.000008 333
Rate C
.40
2 = 1.92
Rate A
· 20
0.000004347
_0.94
(2 decimals) n=
(nearest whole number)
Calculate the value of p (order with respect to the l2)
Experiments AtD 0.0005
0.000004545
0.000004347
0.5M: 1,04
0.0010
p=-0.06
(2 decimals) p=
(nearest whole number)
Write the overall Rate Law: Rate = k[acetone]( D[H*j( \ >[lz](O)
Transcribed Image Text:How measure the rate? I2 is yellow. Will measure how long for it to react (lose its color). So, Rate = A[l2]/Atime Data and Calculations: Table 1. Reactant Volumes & Reaction Times Volume (ml) of: Mixture 4.0 M acetone 1.0 M HCI time (sec) 0.0050 M H20 12 A B 1.00 1.00 230 1.00 1.00 1.00 2.00 1.00 2.00 1.00 106 120 110 1.00 2.00 1.00 1.00 1.00 0.50 2.50 Table 2. Initial Concentrations & Rate of Reaction Mixture A B [acetone] .80 M [H*] .20 M [k] .0010 M Rate =A[la]/time 4.34 x 10-6 9.43 x 10 -6 1.6 M .80M •20M 0010M .0010 4 0005M 8.33 x 10-6 4.54 x lo-G .40M D • 80 M - 20 M The Dilution Factor Method: Original V (4M)(1 ml) = .8M (5 ml) Final Total V Reactant Order Determination Calculate the value of m (order with respect to acetone) 1.6 0.000009433 2= 2.17 Rates = k[ace]m[ÁT Ratea = k[ace]™[H] 0.8 0.000004347 1.12 (2 decimals) m=, (nearest whole number) m = Calculate the value of n (order with respect to the H*) 0.000008 333 Rate C .40 2 = 1.92 Rate A · 20 0.000004347 _0.94 (2 decimals) n= (nearest whole number) Calculate the value of p (order with respect to the l2) Experiments AtD 0.0005 0.000004545 0.000004347 0.5M: 1,04 0.0010 p=-0.06 (2 decimals) p= (nearest whole number) Write the overall Rate Law: Rate = k[acetone]( D[H*j( \ >[lz](O)
Determination of the Rate Constant, k
mixture
A
В
C
D
average
2.71 x 10-5 2.94 x 10-5 2.60x1o-5 2.84 x 10 -52.76x10-5
k
Example: Ratea = k[ace]m[H*]*[l2]° klace]'C H+]' [l2]°
%3D
A :4.34x 10-6
(0.80)'CO.20)'CO.0010)0
= 2.71 x 10-5
B: 9.43 x 10-6
(1.6)'L0.20)' Co.0010)°
= 2.94 x10:5
C: 8. 33 x 10-6
= 2.60 x lo-5
Co.80)'CO.40)'CO.0010)0
D: 4.54 x1o - C
= 2.84 X10- 5
Co.80)'C0.20)' C0.0005)0
Prediction of a Reaction Rate
Use
your average k and these concentrations to predict the reaction rate.
[acetone] = 1.2 M, [H*] = .15 M, [l2] = .002 M
%3D
Rate =
2.76 x 16-5(1.2)'(o.15)'C0.002)° = 4.97 x10-6
0.002M
- 402 seconds
Therefore, Atime = All2]
Rate
Rate = All2]
4.97x10-6
Atime
Use this last equation to predict how long, in seconds,
it will take for the l2 to disappear.
Transcribed Image Text:Determination of the Rate Constant, k mixture A В C D average 2.71 x 10-5 2.94 x 10-5 2.60x1o-5 2.84 x 10 -52.76x10-5 k Example: Ratea = k[ace]m[H*]*[l2]° klace]'C H+]' [l2]° %3D A :4.34x 10-6 (0.80)'CO.20)'CO.0010)0 = 2.71 x 10-5 B: 9.43 x 10-6 (1.6)'L0.20)' Co.0010)° = 2.94 x10:5 C: 8. 33 x 10-6 = 2.60 x lo-5 Co.80)'CO.40)'CO.0010)0 D: 4.54 x1o - C = 2.84 X10- 5 Co.80)'C0.20)' C0.0005)0 Prediction of a Reaction Rate Use your average k and these concentrations to predict the reaction rate. [acetone] = 1.2 M, [H*] = .15 M, [l2] = .002 M %3D Rate = 2.76 x 16-5(1.2)'(o.15)'C0.002)° = 4.97 x10-6 0.002M - 402 seconds Therefore, Atime = All2] Rate Rate = All2] 4.97x10-6 Atime Use this last equation to predict how long, in seconds, it will take for the l2 to disappear.
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