What is the name of this ion? Cr₂O7²- Note: You must include the word "ion." CN [C=N]] cyanide ion acetate ion CH3CO₂ (or ethanoate ion) H₂C CO3²- carbonate ion hydrogen carbonate ion HCO3 (or bicarbonate ion) NO₂ nitrite ion NO₂™ nitrate ion PO43- phosphate ion HPO42- hydrogen phosphate ion H₂PO4 dihydrogen phosphate ion 0=a 0=00=4 20=20= io of OH- SO₂²- SO4 2- HSO4 C10- C10₂ C103 C104 CrO4 2- Cr₂O7²- MnO4 [O-H]] [ OS 5!!!! [c—o] %0 is I hydroxide ion sulfite ion sulfate ion hydrogen sulfate ion (or bisulfate ion) hypochlorite ion chlorite ion chlorate ion perchlorate ion chromate ion dichromate ion permanganate ion

What is the name of this ion? Cr₂O7²- Note: You must include the word "ion." CN [C=N]] cyanide ion acetate ion CH3CO₂ (or ethanoate ion) H₂C CO3²- carbonate ion hydrogen carbonate ion HCO3 (or bicarbonate ion) NO₂ nitrite ion NO₂™ nitrate ion PO43- phosphate ion HPO42- hydrogen phosphate ion H₂PO4 dihydrogen phosphate ion 0=a 0=00=4 20=20= io of OH- SO₂²- SO4 2- HSO4 C10- C10₂ C103 C104 CrO4 2- Cr₂O7²- MnO4 [O-H]] [ OS 5!!!! [c—o] %0 is I hydroxide ion sulfite ion sulfate ion hydrogen sulfate ion (or bisulfate ion) hypochlorite ion chlorite ion chlorate ion perchlorate ion chromate ion dichromate ion permanganate ion

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table: cation 2 + Zn 3+ Fe K + + Cu anion 2- So 4 NO, 3 IO BrO₂ some ionic compounds empirical formula || ■ name of compound X Ś
Table 7a: Formula → name formula Binary? Covalent or Polyatomic ion? Cation variable Name ionic or acid charge? What? Name? 1.Au(NO3)3 2. Сaз(РO,)2 3. Cl20 4. LiH No ionic Yes, Gold(II) Gold 111) Nitrate calcıumphosphate Dichbire monor ide. Lithiam Hudride. Sadiumchlorate Aluminunchlorde yes, Nklel TT) NIckel (u) Cyanide Yes, nitrate NO NO yes 1onic Covalent loniç Tonic onic lonic Covalent yıs,phosphate NO NO NO yeschlorate NO NO 5. NaCIO3 6. AICI3 7. Ni(CN)2 8. P4O10 9. SnSO3 10. (NH4)2CO3 11. CrO3 12. Ba(C2H3O2)2 13. ICI5 NO ves NO yes Nes,cuanide NO lonic Yes NO Ammoniom Carbonate NO Barium Acetate lodıne pentachloride Lead iv) Sultide |calcium phosphate NO lonic yes 14. PbS2 15. СазРО:)2 yes lonic Jonic yes NO no yes
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Br NaNH2 NH3 H,C
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"What is the name of the ion with the formula Sn2+? Do not put the word ""ion"" in your answer. OH- would be entered as hydroxide." "What is the name of the ion with the formula NO3-? Do not put the word ""ion"" in your answer. OH- would be entered as hydroxide." "What is the name of the ion with the formula HCO 3 -? Do not put the word ""ion"" in your answer. OH - would be entered as hydroxide." "What is the name of the ion with the formula Mg2+? Do not put the word ""ion"" in your answer. OH- would be entered as hydroxide."
Give detailed Solution with explanation needed..don't give Handwritten answer .don't use Ai for answering this
Fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table: cation 3+ Co 2+ Fe Continue Cu anion 3- PO co C103 Some ionic compounds empirical formula name of compound X
As seen in the table, compounds containing an integer ratio of elements depend on how many cations combine with how many anions to form a stable compound. For example, in table 1, to form a NaCl compound, first Na ionizes from the Na+ cation which is having +1 positive charge, which will lose 1 electron, it is having +1 charge, this electron then goes to Cl and it will change to Cl- anion by gaining the electron, so here 1:1 ratio charge which means 1 Na+ combines with 1 Cl-1 to form NaCl. So here integer ratio is 1:1 for this sodium chloride compound. As listed in table 2, Mg(OH)2, the integer ratio is 1:2 which means, Mg is a neutral atom that loses 2 electrons and forms an Mg+2 cation, which combines with OH which gains 1 electron to form OH- anion, So here Mg2+ can combine with 2 OH- anion, so they both combine to form Mg(OH)2 which has integer ratio as 1:2 . Thus, atom forms as ions by losing or gaining electrons and combines together in whole number ratio to form stable…