What is the EO value for the Galvanic cell formed from these two half-reactions? PbO2(s) + 3 H* (aq) + HSO4 (aq) + 2e2 PBSO4(s) + 2 H20() E0 = 1.690 V %3D E0 = -0.356 V PbSO4(s) + H* (aq) + 2e 2 Pb(s) + HSO4 (aq) O a. -2.046 V O b. +2.758 V O C. +1.334 V O d. +2.046 V
What is the EO value for the Galvanic cell formed from these two half-reactions? PbO2(s) + 3 H* (aq) + HSO4 (aq) + 2e2 PBSO4(s) + 2 H20() E0 = 1.690 V %3D E0 = -0.356 V PbSO4(s) + H* (aq) + 2e 2 Pb(s) + HSO4 (aq) O a. -2.046 V O b. +2.758 V O C. +1.334 V O d. +2.046 V
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 134CWP
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![QUESTION 25
What is the E value for the Galvanic cell formed from these two half-reactions?
PbO2(s) + 3 H*(aq) + HSO4 (aq) + 2e 2 PBSO4(s) + 2
H20()
E0 = 1.690 V
E0 = -0.356 V
PBSO4(s) + H*(aq) + 2e2 Pb(s) + HSO4 (aq)
O a. -2.046 V
O b. +2.758 V
O c. +1.334 V
O d. +2.046 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f27e7db-af7a-463a-955e-c32ca3cdcdcc%2F40cab026-410a-44e6-9beb-1da86eb2991b%2Fcrc5fmj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 25
What is the E value for the Galvanic cell formed from these two half-reactions?
PbO2(s) + 3 H*(aq) + HSO4 (aq) + 2e 2 PBSO4(s) + 2
H20()
E0 = 1.690 V
E0 = -0.356 V
PBSO4(s) + H*(aq) + 2e2 Pb(s) + HSO4 (aq)
O a. -2.046 V
O b. +2.758 V
O c. +1.334 V
O d. +2.046 V
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