What is the overall cell reaction of a galvanic cell employing the following half-reactions?NiO₂ (s) + 2H₂O + 2e¯ Ni(OH)₂(s) + 2OH(aq), E°NiO2= 0.49 V;Fe(OH)₂(s) + 2e ⇒Fe(s) + 2OH¯(aq), E° Fe(OH)2= -0.88 V.Ni(OH)2(s) + Fe(OH)2(s) → NiO₂(s) + Fe(s) + 2H₂ONiO₂ (s) + Fe(s) + 2H₂O → Ni(OH)2(aq) + Fe(OH)2(aq)O NiO₂ (s) + 2Fe(s) + 2H₂O → Ni(OH)2(s) + 2Fe(OH)2(s)NiO₂ (s) + Fe(s) + 2H₂O → Ni(OH)2(s) + Fe(OH)2(s)OOOHintWhat is the standard cell potential of a galvanic cell?E cellIncorrect.=

Given : half cell reaction Tip : cell having higher value of reduction potential will reduced

What is the overall cell reaction of a galvanic cell employing the following half-reactions? NiO2 (s) + 2H₂O + 2e Ni(OH)₂(s) + 2OH(aq), E°NiO2= 0.49 V; Fe(OH)2(s) + 2e Fe(s) + 2OH(aq), E° Fe(OH)2= -0.88 V. Z Hint NI(OH)2(s) + Fe(OH)2(s) → NiO2 (s) + Fe(s) + 2H₂O NiO₂ (s) + Fe(s) + 2H₂O → Ni(OH)₂(aq) + Fe(OH)2(aq) NiO₂ (s) + 2Fe(s) + 2H₂O → Ni(OH)2(s) + 2Fe(OH)2(s) NiO₂ (s) + Fe(s) + 2H₂O → Ni(OH)2(s) + Fe(OH)2(s) E cell What is the standard cell potential of a galvanic cell? = Incorrect. V

What is the overall cell reaction of a galvanic cell employing the following half-reactions? NiO2 (s) + 2H₂O + 2e Ni(OH)₂(s) + 2OH(aq), E°NiO2= 0.49 V; Fe(OH)2(s) + 2e Fe(s) + 2OH(aq), E° Fe(OH)2= -0.88 V. Z Hint NI(OH)2(s) + Fe(OH)2(s) → NiO2 (s) + Fe(s) + 2H₂O NiO₂ (s) + Fe(s) + 2H₂O → Ni(OH)₂(aq) + Fe(OH)2(aq) NiO₂ (s) + 2Fe(s) + 2H₂O → Ni(OH)2(s) + 2Fe(OH)2(s) NiO₂ (s) + Fe(s) + 2H₂O → Ni(OH)2(s) + Fe(OH)2(s) E cell What is the standard cell potential of a galvanic cell? = Incorrect. V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Use the Nernst equation to determine the cell potential, Ecell, of the galvanic cell consisting of the following half-cell systems: Ag+(0.010M) + e- --> Ag Eo= +0.80 V Cr3+(O.010M) + 3e- --> Cr Eo= -0.74 V
Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25°C. Mg(s) ∣ Mg2+(aq, 1.74 M) || Cu2+(aq, 0.0053 M) ∣ Cu(s)
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What is the cell potential (EO) for a galvanic cell formed from the following two half-reactions? PbO2(s) + 3 H*(a) + HSO4-(aq) + 2 e-+ PBSO4(s) + 2 E° = 1.690 V %3D H20(1) PbSO4(s) + H*(aq) + 2 e- → Pb(s) + HSO4-(aq) E° = -0.356 V (A) +1.334 V (B) -2.046 V c) +2.046 V D) +2.758 V
For the galvanic cell: Zn(s) + 2Tl+(aq) 2Tl(s) + Zn2+(aq) Eocell = 0.42 V The standard reduction potential for the half cell Zn2+(aq) + 2e– Zn(s) is Eored = –0.76 V What is the standard reduction potential for Tl+(aq) + e– Tl(s) Eored = ? V a. +0.17 V b. –0.17 V c. –0.34 V d. +0.34 V
(ii) State which species is the oxidising agent.
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3) Draw a picture of the galvanic cell represented by the line notation below and then write the reduction half-reactions for each electrode. Also identify the anode and cathode for each half cell. Pt (s) | Fe3+ (aq), Fe2+ (aq) || Cr2O72-(aq), Cr3+ (aq), HA (aq) | Pt (s)