The two half cells that make up a battery are shown below with their reduction potentials Br2(aq) + 2e* → 2Br*(aq); E= 1.07 V Cu2+(aq) + e → Cu*(aq); E= 0.16 V What is the equation for the galvanic cell made with these two half equations? Oa. 2Cu*(aq) + Br2(aq) → 2Cu²*(aq) + 2B1°(aq) Ob. 2Cu2*(aq) + Br2(aq) → 2Cu*(aq) + 2Br"(aq) Oc. 2Cu*(aq) + 2Br"(aq) → 2Cu²*(aq) + Br2(aq) Od. 2Cu²*(aq) + 2B1°(aq) → 2Cu*(aq) + Br2(aq) Oe. None of the other options
The two half cells that make up a battery are shown below with their reduction potentials Br2(aq) + 2e* → 2Br*(aq); E= 1.07 V Cu2+(aq) + e → Cu*(aq); E= 0.16 V What is the equation for the galvanic cell made with these two half equations? Oa. 2Cu*(aq) + Br2(aq) → 2Cu²*(aq) + 2B1°(aq) Ob. 2Cu2*(aq) + Br2(aq) → 2Cu*(aq) + 2Br"(aq) Oc. 2Cu*(aq) + 2Br"(aq) → 2Cu²*(aq) + Br2(aq) Od. 2Cu²*(aq) + 2B1°(aq) → 2Cu*(aq) + Br2(aq) Oe. None of the other options
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The two half cells that make up a battery are shown below with their reduction potentials:
Br2(aq) + 2e → 2B1¯(aq); E= 1.07 V
Cu²+(aq) + e – Cu*(aq); E= 0.16 V
What is the equation for the galvanic cell made with these two half equations?
Oa. 2Cu*(aq) + Br2(aq) – 2Cu2+(aq) + 2Br (aq)
Ob. 2Cu2*(aq) + Br2(aq) → 2Cu*(aq) + 2Br"(aq)
Oc. 2Cu*(aq) + 2Br (aq) – 2Cu²* (aq) + Br2(aq)
Od. 2Cu2*(aq) + 2B1°(aq) → 2Cu*(aq) + Br2(aq)
Oe. None of the other options](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab91d1b5-ede7-48e5-a83f-e0cd561bedca%2Fba71be09-2314-488b-b58d-eee39d1d279a%2F11pjmpa_processed.png&w=3840&q=75)
Transcribed Image Text:The two half cells that make up a battery are shown below with their reduction potentials:
Br2(aq) + 2e → 2B1¯(aq); E= 1.07 V
Cu²+(aq) + e – Cu*(aq); E= 0.16 V
What is the equation for the galvanic cell made with these two half equations?
Oa. 2Cu*(aq) + Br2(aq) – 2Cu2+(aq) + 2Br (aq)
Ob. 2Cu2*(aq) + Br2(aq) → 2Cu*(aq) + 2Br"(aq)
Oc. 2Cu*(aq) + 2Br (aq) – 2Cu²* (aq) + Br2(aq)
Od. 2Cu2*(aq) + 2B1°(aq) → 2Cu*(aq) + Br2(aq)
Oe. None of the other options
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