Answered: What is the empirical formula of a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the empirical formula of a compound that contains 2.47% H, 59.53% O, and 38.00% P? Type the subscript of each element in the corresponding box.

The subscript of H is , the subscript of O is , and the subscript of P is

Expert Solution

Step 1

Given : Mass percent of P = 38.00 %

Mass percent of H = 2.47 %

And mass percent of O = 59.53 %

Assuming the empirical formula of the compound is H_aP_bO_c and mass of sample 100 g.

Hence the mass of elements in the compound are given by,

$= > M a s s o f P = \frac{M a s s o f s a m p l e X m a s s p e r c e n t o f P}{100} = \frac{38.00 X 100}{100} = 38.00 g = > M a s s o f H = \frac{M a s s o f s a m p l e X m a s s p e r c e n t o f H}{100} = \frac{2.47 X 100}{100} = 2.47 g = > M a s s o f O = \frac{M a s s o f s a m p l e X m a s s p e r c e n t o f O}{100} = \frac{59.53 X 100}{100} = 59.53 g$

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