Determine the empirical formula of a compound that is 31.63% 09 31.56 % Ti and 36.81% Fe by mass Fe Ti A Moving to another question will save this response.
Determine the empirical formula of a compound that is 31.63% 09 31.56 % Ti and 36.81% Fe by mass Fe Ti A Moving to another question will save this response.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Question 9
**Problem Statement:**
Determine the empirical formula of a compound that is 31.63% O, 31.56% Ti, and 36.81% Fe by mass.
**Elements:**
- Fe (Iron)
- Ti (Titanium)
- O (Oxygen)
**Instructions:**
- Moving to another question will save this response.
**Explanation for Educational Context:**
To determine the empirical formula, follow these steps:
1. **Convert percentages to grams** (assuming 100 g of the compound for simplicity):
- O: 31.63 g
- Ti: 31.56 g
- Fe: 36.81 g
2. **Convert grams to moles** using molar masses:
- Molar mass of O = 16.00 g/mol
- Molar mass of Ti = 47.87 g/mol
- Molar mass of Fe = 55.85 g/mol
3. **Calculate moles for each element**:
- Moles of O = 31.63 g / 16.00 g/mol
- Moles of Ti = 31.56 g / 47.87 g/mol
- Moles of Fe = 36.81 g / 55.85 g/mol
4. **Find the simplest whole number ratio**:
- Divide each mole value by the smallest number of moles calculated.
5. **Write the empirical formula** using these ratios to represent the proportions of each element in the compound.
Proceed with the calculations and use these principles to complete the question.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F394d8541-a3b5-4cf5-865d-319b45552e6b%2F75eb9903-b258-49a5-a551-b3259e83c70c%2F353olqh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question 9
**Problem Statement:**
Determine the empirical formula of a compound that is 31.63% O, 31.56% Ti, and 36.81% Fe by mass.
**Elements:**
- Fe (Iron)
- Ti (Titanium)
- O (Oxygen)
**Instructions:**
- Moving to another question will save this response.
**Explanation for Educational Context:**
To determine the empirical formula, follow these steps:
1. **Convert percentages to grams** (assuming 100 g of the compound for simplicity):
- O: 31.63 g
- Ti: 31.56 g
- Fe: 36.81 g
2. **Convert grams to moles** using molar masses:
- Molar mass of O = 16.00 g/mol
- Molar mass of Ti = 47.87 g/mol
- Molar mass of Fe = 55.85 g/mol
3. **Calculate moles for each element**:
- Moles of O = 31.63 g / 16.00 g/mol
- Moles of Ti = 31.56 g / 47.87 g/mol
- Moles of Fe = 36.81 g / 55.85 g/mol
4. **Find the simplest whole number ratio**:
- Divide each mole value by the smallest number of moles calculated.
5. **Write the empirical formula** using these ratios to represent the proportions of each element in the compound.
Proceed with the calculations and use these principles to complete the question.
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