Question Help VIn a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measuredbefore and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.8 and a standard deViation of 19.8.Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest aboutthe effectiveness of garlic in reducing LDL cholesterol?Click here to view at distribution table.Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.tsWhat is the confidence interval estimate of the population mean p?SSmg/dL%&2$4@#5678.923tyuierw/ to two decimal places as needed.)What does the confidence interval suggest about the effectiveness of the treatment?OA. The confidence interval limits contain 0, suggesting that the garlic treatment did affect the LDL cholesterol levels.B. The confidence interval limits do not contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels.OC. The confidence interval limits contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels.OD. The confidence interval limits do not contain 0, suggesting that the garlic treatment did affect the LDL cholesterol levels.Click to select your answer(s).Ce#3%232$5789-rtyu<6个

Name: Question Help VIn a test of the effectiveness of garlic for lowering
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Question Help VIn a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measuredbefore and after the treatment. The changes (before-after) in their le

Answered: What is the confidence interval…

Math

Statistics

What is the confidence interval estimate of the population mean u? mg/dL

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

An IQ test is designed so that the mean is 100 and the standard deviation is 9 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 99% confidence that the sample mean is within 2 IQ points of the true mean. Assume that o = 9 and determine the required sample size using technology. Then determine if this is a reasonable sample size for a real world calculation. The required sample size is. (Round up to the nearest integer.) Would it be reasonable to sample this number of students? No. This number of IQ test scores is a fairly small number. Yes. This number of IQ test scores is a fairly large number. No. This number of IQ test scores is a fairly large number. Yes. This number of IQ test scores is a fairly small number.
What price do farmers get for their watermelon crops? In the third week of July, a random sample of 40 farming regions gave a sample mean of x = Assume that o is known to be $1.92 per 100 pounds. $6.88 per 100 pounds of watermelon. (a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop (in dollars). What is the margin of error (in dollars)? (For each answer, enter a number. Round your answers to two decimal places.) lower limit $ upper limit 2$ margin of error $ (b) Find the sample size necessary for a 90% confidence level with maximal error of estimate E = 0.27 for the mean price per 100 pounds of watermelon. (Enter a number. Round up to the nearest whole number.) farming regions (c) A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop (in dollars). What is the margin of error (in dollars)? Hint: 1 ton is 2000 pounds. (For each…
Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value ta/2. (b) find the critical value z/2, or (c) state that neither the normal distribution nor the t distribution applies. The confidence level is 95%, o is not known, and the histogram of 62 player salaries (in thousands of dollars) of football players on a team is as shown.
Give a 99.8% confidence interval, for µ1 - µ2 given the following information. 2.04, s1 = 0.39 20, ã1 60, x2 = 2.37, 82 - 0.7 n2 Use Technology Rounded to 2 decimal places.
Is the birth rate of the infants in this sample significantly different from that of the general population at alpha level of 0.05? Explain your response.
just the last part thank you!
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 20 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o = 0.32 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) O normal distribution of weights Oo is known O n is large O o is unknown O uniform distribution of weights (c) Interpret your results in the context of this problem. O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20. O we are 80% confident that the true average weight of Allen's hummingbirds falls…
Which alternative hypotheses will allow you to determine statistical significance at α = 0.05 using a 95% confidence interval? H a: μ = 30 H a: μ > 30 H a: μ ≠ 30 H a: μ <30
subjects with high cholestrol After two months of taking the drug, the decrease in cholestrol level is e =75 and the rescarchen assumes that the decrease in cholestrol follows a normal distribution,with unknown mean u and standard deviation o = 15. Construct a A medical rescarcher treats 400 using a rewdrug. average 99% confidence interval for Me
A. True or False? A researcher compares the BMI of two populations of individuals from different socioeconomic backgrounds and finds that the proportion of individuals considered obese and from a poor background is .37 (n = 112), and the proportion of individuals considered obese and from an affluent background is .27 (n = 87); a 95% confidence interval for the risk difference for obesity among members of the poor population compared to the affluent population is (-0.03, 0.23). B. Why is it true or false?
What critical value of t* should be used for a 99.5% confidence interval for the population mean based upon a random sample of 18 observations? Find the t-table here. t* = 2.878 t* = 2.898 t* = 3.197 t* = 3.222
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 12 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with a = 0.22 gram. When finding an 80% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) Oo is known Oo is unknown O uniform distribution of weights O normal distribution of weights On is large (c) Interpret your results in the context of this problem. We are 80% confident that the true average weight of…