Using the results below:M1 = 18.57,M2 = 18.33, SM1-M2 = 0.97,tcv = 1.9971. Calculate a 95% confidence interval estimating the true difference between the population means.Write the final answer in brackets [x.xx, x.xx].2. Based on your answer, explain whether there is a significant difference between the two populationmeans. What about your answer tells you whether there is a significant difference or not?

It is given that M1=18.57, M2=18.33, SM1-M2=0.97 and tcv=1.997.

Answered: Using the results below: M1 = 18.57, M2…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What are the confidence intervals for: Mean= 5.9 Sd= 3 N=200 α= .01
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The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14). State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why? 22.95 is in the center of the interval. The means are definitely not different. 22.95 is just outside the 95% confidence interval. Can't say the means are really different. 22.95 is not equal to 20.7. The means are definitely different. 20.7 is just outside the 95% confidence interval. Can't say the means are really different.
Construct the 99% confidence interval for the difference m1-m2 when x bar = 476.88, x bar = 318.32, s1=42.11, s2= 26.80, n1=19, and n2=22. Use the ti 84 calculator and round the answers to two decimal places. A 99% confidence interval for the difference in the population means is ?
A. True or False? A researcher compares the BMI of two populations of individuals from different socioeconomic backgrounds and finds that the proportion of individuals considered obese and from a poor background is .37 (n = 112), and the proportion of individuals considered obese and from an affluent background is .27 (n = 87); a 95% confidence interval for the risk difference for obesity among members of the poor population compared to the affluent population is (-0.03, 0.23). B. Why is it true or false?
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