A doctor would like to estimate the mean difference in height of pairs of identical twins. The doctor randomly selects 8 pairs of identical twins and determines the current height, in inches, of each twin. The data are displayed in the table.     The conditions for inference are met. The 95% confidence interval for the mean difference (twin 1 – twin 2) in height is (–0.823, 0.573). What is the correct interpretation of this interval? The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean height of twins. The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean height of twins in this sample. The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean difference in the height of twins. The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean difference in the height of the twins in this sample.

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A doctor would like to estimate the mean difference in height of pairs of identical twins. The doctor randomly selects 8 pairs of identical twins and determines the current height, in inches, of each twin. The data are displayed in the table.

 

 

The conditions for inference are met. The 95% confidence interval for the mean difference (twin 1 – twin 2) in height is (–0.823, 0.573). What is the correct interpretation of this interval?

The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean height of twins.
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean height of twins in this sample.
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean difference in the height of twins.
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean difference in the height of the twins in this sample.

 

selects 8 pairs of identical twins and determines the current height, in inches, of each twin. The data are displayed
in the table.
Pair
1
2
3
4
5
6
7
8
Twin 1
66
64.5
72
70
65 64.5
48 54
Twin 2
67
65 72 69.5 65 63 49 54.5
The conditions for inference are met. The 95% confidence interval for the mean difference (twin 1 - twin 2) in
height is (-0.823, 0.573). What is the correct interpretation of this interval?
O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean
height of twins.
O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean
height of twins in this sample.
O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean
difference in the height of twins.
O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean
difference in the height of the twins in this sample.
Transcribed Image Text:selects 8 pairs of identical twins and determines the current height, in inches, of each twin. The data are displayed in the table. Pair 1 2 3 4 5 6 7 8 Twin 1 66 64.5 72 70 65 64.5 48 54 Twin 2 67 65 72 69.5 65 63 49 54.5 The conditions for inference are met. The 95% confidence interval for the mean difference (twin 1 - twin 2) in height is (-0.823, 0.573). What is the correct interpretation of this interval? O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean height of twins. O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean height of twins in this sample. O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean difference in the height of twins. O The doctor can be 95% confident that the interval from -0.823 inches to 0.573 inches captures the true mean difference in the height of the twins in this sample.
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