What hit ratio is required to reduce the effective memory access time, from 200 nsecs to 140 nsecs, if the cache access time is 20 nsec?
Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
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Q: What hit ratio is required to reduce the effective memory access time, from 200 nsecs effective…
A: Given data is effective memory access time from 200 nano - secs to 140 nano-secs
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Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
A: Given: Using the direct-mapped cache design with a 32-bit address. Offset(4-0) : which means…
Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
A: Directly Mapped : Index Bits = 4 Offset : 6 Total bits : 32
Q: Calculate the block number of the main memory for the address 722542 (decimal).
A: Answer:The block number of the main memory is 5645.
Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
A: The correct answer for the above mentioned question is given in the following steps for your…
Q: alculate the hit time at L2 cache in a 1.3GHz. processor assuming that the global average memory…
A: Given Data : Frequency = 1.3 GHz Average memory access time = 5.81 cycles Hit rate at L1 = 0.91%…
Q: Calculate the Effective Access Time (EAT) by assuming the Hit ratio (?) 95%. Cache Access Time (ε)…
A: Given, Hit ratio (?)= 0.95 Cache Access Time (ε)=20 microsecond Memory Access Time (T) = 100…
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Q: re there in a set? ANSWER: cache has? ANSWER: address format is => | Tag: blocks sets bits | Set:…
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Q: e access tim ess time of c -1 is thrice th ty from the L ock cycles. T of the system
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Q: Index Tag Tag (binary) | (8 bits) 1 Valid 00 01 (8 bits) | Valid 10 86 42 69 FD 11 000 AF BC 19 6D 1…
A: The maximum size of met in kb is =25 =64 kb
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Q: that in 1000 memory references there are 50 misses in the first-level cache, 20 misses in the…
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Q: Assume the address format for a fully-associative cache is as follows: 6 bits 2 bits Tag Offset…
A: please see the next step for solution
Q: For a direct-mapped cache design with a 64-bit address, the following bits of the address are used…
A:
Q: For a direct-mapped cache design with a 32-bit address, the following bits of the address are used…
A: Dear learner, hope you are doing well, I will try my best to answer this question. Thank You!!…
What hit ratio is required to reduce the effective memory access time, from 200 nsecs to 140 nsecs, if the cache access time is 20 nsec?
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- Assume the address format for a fully-associative cache is as follows: Tag Offset b Given the cache directory is as shown in the diagram below, indicate whether the memory reference OxDA results in a cache hits or a miss. Tag valid Block 000 110110 1 000001 1 001 010 ? 000010 011 000101 100 001000 101 100010 110 010111 110110 O Miss Hit D 111 1 1 1 0 0 1Calculate the hit time at L2 cache in a 1.3GHz. processor assuming that the global average memory access time is 5.81 cycles, the hit rate at L1 is 0.91%, the miss penalty at L2 is 88 cycles, the number of misses at L2 is 52 and the number of misses at L1 is 4109. Give the result in ns.find the hit ratio
- For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache: Tag Index Offset 31-10 9-6 5-0 1. What is the cache block size (in words)? 2. How many entries does the cache have? 3. What is the ratio between total bits required for such a cache implementation over the data storage bits?A computer system has a 128 byte cache. It uses four-way set-associative mapping with 8 bytes in each block. The phy 32 bits, and the smallest addressable unit is 1 byte. (i) To what block frames of the cache can the address 000010AFH be assigned? (ii) If the addresses 000010AFH and FFFF7AXYH can be simultaneously assigned to the same Cache set, what values digits X and Y have?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. What is the ratio between total bits required for such a cache implementation over the data storage bits?
- For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many words of data are included in one cache line?Consider a cache system with blocks of 24 words, and words of 23 bytes. Calculate the block number of the main memory for the address 722542 (decimal). Note: The anwer has to be provided in decimal (advise: convert 722542 to binary, work in binary and trasform the final solution from binary to decimal).If memory read cycle takes 100 ns and a cache read cycle takes 20 ns, then for four continuous references, the first one brings the main memory contents to cache and the next three from cache. Find the time taken for the Read cycle with and without Cache? What is the Percentage speedup obtained?
- A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.For a direct-mapped cache design with a 32-bit address, the following bitsof the address are used to access the cache. Use the table below. a. What is the cache block size (in words)?b. How many entries does the cache have?c. What is the ration between total bits required for such a cache implementation overthe data storage bit?Suppose that in 1000 memory references there are 50 misses in the first-level cache, 20 misses in the second-level cache, and 5 misses in the third-level cache. Assume the miss penalty from the L3 cache to memory is 100 clock cycle, the hit time of the L3 cache is 10 clocks, the hit time of the L2 cache is 4 clocks, the hit time of L1 is 1 clock cycle. What is the average memory access time?