what can you conclude concerning the null hypothesis?
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A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…
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Q: Suppose 249 subjects are treated with a drug that is used to treat pain and 53 of them developed…
A: Solution To test the hypothesis we will use Excel
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- 2. Identify the null hypothesis, alternative hypothesis, test statistic, p-value(s), conclusion about the null hypothesis, and final conclusion that addresses the original claim. In a study of 11,000 car crashes, it was found that 5720 of them occurred within 5 miles of home (based on data from Progressive Insurance). Use a 0.01 significance level to test the claim that more than 50% of car crashes occur within 5 miles of homes. Are the results questionable because they are based on a survey sponsored by an insurance company?In a study of 817 randomly selected medical malpractice lawsuits, it was found that 495 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? A. H0: p=0.5 H1: p≠0.5 B. H0: p=0.5 H1: p>0.5 C. H0: p=0.5 H1: p<0.5 D. H0: p<0.5 H1: p=0.5 E. H0: p>0.5 H1: p=0.5 F. H0: p≠0.5 H1: p=0.5 What is the test statistic? z=nothing (Round to two decimal places as needed.) What is the P- P-value= (Round to three decimal places as needed.)Suppose 450 subjects are treated with a drug that is used to treat pain and 140 of them developed nausea. Use a 0.05 significance level to test the claim that more than 205% of users develop nausea. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Show word count ( Previous Next
- A concerned group of citizens wanted to know if the proportion of armed robberies in Texas was different in 2011 than in 2010. Their research showed that of the 113,231 violent crimes in Texas in 2010, 7,622 of them were armed robberies. In 2011, 7,439 of the 104,873 violent crimes were in the armed robbery category. Test at a 5% significance level.a) The null and alternative hypothesis would be: �0:�2010=�2011�1:�2010≠�2011 �0:�2010=�2011�1:�2010<�2011 �0:�2010=�2011�1:�2010≠�2011 �0:�2010=�2011�1:�2010>�2011 �0:�2010=�2011�1:�2010>�2011 �0:�2010=�2011�1:�2010<�2011 b) Determine the test statistic. Round to two decimals.�=c) Find the p-value and round to 4 decimals.p = d) Make a decision. Fail to reject the null hypothesis Reject the null hypothesis e) Write the conclusion. There is not sufficient evidence to support the claim that the proportion of armed robberies is different in 2011 than 2010. There is sufficient evidence to support the claim that the…Suppose we are interested in the relationship between individuals’ place of residence (rural versus urban) and their political affiliation (Republican versus Democrat). A random sample of 100 individuals yields the following crosstabulation: Political Affiliation Place of Residence Republican Democrat Rural 21 29 Urban 14 36 a) In words, what is the null hypothesis to be tested? b) Is the relationship between place of residence and political affiliation statistically significant at the .05 level? (Be sure to show the statistics that lead to your decision.) c) Compute and interpret an appropriate measure of association for the relationship between these two variables.Christine, a researcher in psychology and biobehavioral health, believes that city residents and residents of rural areas differ in how appealing they find owning a cat. A random sample of 109 people who live in San Antonio were surveyed and 59 identified themselves as a "cat person." A random sample of 108 people who live in the surrounding rural area were selected and 72 identified themselves as a "cat person." Conduct an appropriate hypothesis test at the a = 0.1 significance level to test Christine's claim. Round answers to 4 decimal places where appropriate. a. State the null and alternative hypotheses. Ho: p. H₁: p. b. What is the appropriate distribution to use for the hypothesis test? Z (Normal) c. Find the test statistic. Test Statistic: -1.9593 X d. Determine the P-value: op. P-value: 0.0501 X O p.
- US Universities found that 72% of people are concerned about the possibility that their personal records could be stolen over the internet. If a random sample of 300 college students at a Midwestern university were taken and 228 of them were concerned about the possibility that their personal records could be stolen over the Internet, could you conclude at the 0.025 level of significance that a higher proportion of the university’s college students are concerned about Internet theft than the public at large? Report the p-value for this test. Z0.025 = 1.964. Chantix (varenicline) tablets are used as an aid to help people stop smoking. In a clinical trial, 129 subjects were treated with Chantix twice a day for 12 weeks, and 16 subjects experienced abdominal pain (based on data from Pfizer, Inc.)If someone claims that more than 8% of Chantix users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of P, the power of the test is 0.96. Interpret this value of the power of the test.A researcher looking for evidence of extrasensory perception (ESP) tests 1000 subjects. Forty-three of these subjects do significantly better (P < 0.05) than random guessing. Forty-three seems like a lot of people, but you cannot conclude that these 43 people have ESP. Why not? The statistical significance level is not be stringent enough to conclude an ESP status. Since the tests were performed at the 5% significance level, as many as 50 subjects may have done significantly better than random guessing just by chance. The sample size was not large enough for any statistical inference. The P-value needs to be below 0.025 to be considered statistically significant given the two-tailed nature of this type of test.
- A large manufacturing company claims that less than 10% of its customers make a complaint about the company’s products. Test this claim at the 10% significance level, if a survey found that 29 out of a random sample of 320 of the company’s customers made a complaint about the company’s products.In a random sample of 108 employees, 25 men earned less than $20 per hour, 25 earned between $20 and $30, and 8 earned more than $30 per hour. In the same study, 29 women earned less than $20 per hour, 15 earned between $20 and $30, and 6 earned more than $30 per hour. Test the hypotheses, at the 10% level of significance, that men and women earn the same. State your conclusion as a sentence including the test statistic and the critical value.
