A newspaper is trying to see if opinions on the death penalty have changed over the last few decades. In 2003,64% of adults said that they approved of the death penalty in some circumstances. The newspaper took arandom sample of 1000 individuals and found that 675 of them were in support of the death penalty.Assuming a 5% significance level, what conclusion should the newspaper draw?O They should reject the null hypothesis; there is no evidence that opinions on the death penalty have changedO They should not reject the null hypothesis; there is evidence that opinions on the death penalty have changedO They should not reject the null hypothesis; there is no evidence that opinions on the death penalty have changedThey should reject the null hypothesis; there is evidence that opinions on the death penalty have changed

Answered: Image /qna-images/answer/abc444a1-7ee0-4efa-a3ef-d9c494a6425c.jpg

Answered: 64% of adults said that they approved…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (Ha) at a significance level of a = 0.01. H.:p1 = p2 Ha:pi > P2 You obtain a sample from the first population with 166 successes and 408 failures. You obtain a sample from the second population with 94 successes and 348 failures. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a
For married couples, is there a significant difference in data usage between the two partners on their smartphones? A random sample of married couples were selected and their data usage over one particular month (chosen at random) was recorded. At the a = 0.10 level of significance, use the data given below to test the claim that there is no difference in data usage between partners. Let µp be the mean of the differences in data usage between partner 1 and partner 2 in each marriage. Assume that the differences have a normal distribution. (Round your results to three decimal places. Which would be correct hypotheses for this test? O Ho: HD = 0, H1: µp 0 O Ho: HD = 0, H1:µD > 0 GB of data used: Partner 1 Partner 2 1.74 3.98 2.53 2.42 4.03 2.42 1.16 3.22 1.93 1.5 3.12 1.43 2.93 2.41 2.76 3.05 2.48 3.28 3.56 2.76 1.33 4.38 3.37 3.47 1.71 2.64 3.81 2.28 Test Statistic:
The table below includes results from polygraph (lie detector) experiments conducted by researchers. In each case, it was known if the subjected lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truth and lies? Click the icon to view the table. ..... Determine the null and alternative hypotheses. A. Ho: Polygraph testing is accurate. H1: Polygraph testing is not accurate. More info B. Ho: Whether a subject lies is independent of the polygraph test indication. H1: Whether a subject lies is not independent of the polygraph test indication. Did the Subject Actually Lie? No (Did Not Lie) Yes (Lied) C. Ho: Whether a subject lies is not independent of the polygraph test indication. H: Whether a subject lies is independent of the polygraph test indication.…
The table below includes results from polygraph (lie detector) experiments conducted by researchers. In each case, it was known if the subjected lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truth and lies? Did Not Lie ; Lied Polygraph indicated lie 13 ; 39 Polygraph indicated no lie 18 ; 10 χ2equals= P-value= Do the results suggest that polygraphs are effective in distinguishing between truth and lies? A.There is not sufficient evidence to warrant rejection of the claim that whether a subject lies is independent of the polygraph test indication. B.There is sufficient evidence to warrant rejection of the claim that whether a subject lies is independent of the polygraph test indication. C.There is not sufficient evidence…
You wish to test the following claim (Ha) at a significance level of a = 0.001. H.:µ = 90.9 H:µ < 90.9 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: 69.3 87.5 77.6 119.2 79.6 71.1 65.5 42.1 93.9 66.2 66.8 128.4 64.8 68.1 96.5 33 69.9 80.2 71.1 100.2 85.3 86.4 82.2 95.8 85.3 94.5 64.8 80.2 79.1 70.5 76.5 95.2 101.9 79.1 92 54.4 51.9 67.5 72.2 77.1 77.1 106.9 109.5 99.4 89.7 44.8 99.4 57.6 70.5 76.5 53.2 66.8 101.1 99.4 94.5 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a
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A news article that you read stated that 58% of voters prefer the Democratic candidate. You think that the actual percent is smaller. 150 of the 300 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.05 level of significance? Interpret the p-value in the context of the study. If the population proportion of voters who prefer the Democratic candidate is 58% and if another 300 voters are surveyed then there would be a 0.25% chance fewer than 50% of the 300 voters surveyed prefer the Democratic candidate. If the sample proportion of voters who prefer the Democratic candidate is 50% and if another 300 voters are surveyed then there would be a 0.25% chance of concluding that fewer than 58% of all voters surveyed prefer the Democratic candidate. There is a 58% chance of a Type I error. There is a 0.25% chance that fewer than 58% of all voters prefer the Democratic candidate. Interpret the level of significance in the context of…
According to the most recent General Social Survey, 70% of adults watch TV nightly. A researcher believes that the proportion of college students who watch TV nightly is less than this. To test this claim the research samples 400 college students and finds that 276 watch TV nightly. At the 0.05 level of significance does this data provide evidence to suggest that the proportion of college students who watch TV nightly is less than 70%? Select the correct conclusion for the hypothesis test: Question 12 options: Fail to reject the null hypothesis because the p-value is less than the level of significance. Fail to reject the null hypothesis because the p-value is greater than the level of significance. Reject the null hypothesis because the p-value is less than the level of significance. Reject the null because the p-value is greater than the level of significance.
It is claimed that in a bushel of peaches, less than 10% are defective. A sample of 400 peaches is examined and 50 are found to be defective. What is the null hypothesis?
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This Question: 5 pts 18 of 20 (6 complete) v This Test: 100 pts possible = Question Help A random sample of 823 births included 435 boys. Use a 0.05 significance level to test the claim that 50.7% of newborn babies are boys. Do the results support the belief that 50.7% of newborn babies are boys? Tdenuiy ne nuii and aiternauve nypouneses for is test. Choose ine correct ariswer pelow. O A. Ho: p= 0.507 H1:p0.507 O D. Ho: p= 0.507 H:p#0.507 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is 1.24 (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is 0.216 (Round to three decimal places as needed.) Click to select your answer(s).
The table below summarizes the results of a survey in which randomly selected people were asked how they felt about the use of marijuana for medical purposes. A chi-square test at a significance level of 5% is used. Feelings on Medical Marijuana In Favor Opposed Undecided Gender: Male: 538 167 29 Female: 557 186 31 What would the null hypothesis be? a. Feelings on Medical Marijuana and gender are dependent. b. Feelings on Medical Marijuana and gender are independent.

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