We need to obtain the following part by OD operation in turning, starting from a 100mmdiameter cylinder. The maximum allowable depth of cut is 3mm. It is required to make a finishingpass with d=1mm and a feed of 0.3mm/revolution.150 mm150 mmThe machine has a total power of 10hp and 85% efficiency. The material has a specific energy500 based onof 25 W/(cm³/min). It is recommended to make the operation at a constant rpm =calculations made for an average diameter.Determine the minimum required time to finish the part.Hint: calculate the maximum material removal rate then the cutting speed for each pass, then the feedrate for each pass and finally the time of cutting.80 mm100 mm

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We need to obtain the following part by OD operation in turning, starting from a 100mm diameter cylinder. The maximum allowable depth of cut is 3mm. It is required to make a finishing pass with d=lmm and a feed of 0.3mm/revolution. 150 mm 150 mm The machine has a total power of 10hp and 85% efficiency. The material has a specific energy 500 based on of 25 W/(cm/min). It is recommended to make the operation at a constant rpm = calculations made for an average diameter. Determine the minimum required time to finish the part. Hint: calculate the maximum material removal rate then the cutting speed for each pass, then the feed rate for each pass and finally the time of cutting. 80 mm 100 mm

We need to obtain the following part by OD operation in turning, starting from a 100mm diameter cylinder. The maximum allowable depth of cut is 3mm. It is required to make a finishing pass with d=lmm and a feed of 0.3mm/revolution. 150 mm 150 mm The machine has a total power of 10hp and 85% efficiency. The material has a specific energy 500 based on of 25 W/(cm/min). It is recommended to make the operation at a constant rpm = calculations made for an average diameter. Determine the minimum required time to finish the part. Hint: calculate the maximum material removal rate then the cutting speed for each pass, then the feed rate for each pass and finally the time of cutting. 80 mm 100 mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A cylindrical rod is machined using turning processes. It is given that the cutting speed is 120min ¹, and feed per tooth is 0.0025 m/min. The outer diameter is 35mm, the length of the rod is 130m and the inner diameter is 22mm. The number of teeth is 6. Find Rotational speed, Feed rate, Machining time, and Depth of cut.
Calculate the r/min required for finish turning a 2in diameter piece of machine steel (The cutting speed of the machine steel is 100).
In a turning operation, cutting speed =200 m/min; feed = 0.25mm mm/rev, and depth of cut = 4.00mm Thermal diffusivity of the work material = 20m mm^2/s and volumetric specific heat =3.5(10^ -3 )J/mm^ 3 -C If the temperature increase above ambient temperature (20degreesC) is the angle measured by a tool-chip thermocouple to be 700degreesC, determine the specific energy for the work material in this operation.
the rod to 16 mm and also facing operation on both sides is done. Assume cutting speed is 30 m/min and a feed of 0.7 mm/rev is used. A mild steel rod having 35 mm diameter and 120 mm length is to be turned on a lathe. Determine the machining time to reduce 20 40 60 035 025 016
For the operation of straight turning in a lathe machine, the diameter of the workpiece is 80 mm, the length is 0.12 m, the cutting speed is 80 m / min, the feed is 0.5 mm / rev and the depth of cut is 0.002 m . Find the material removing rate and the time of machining.