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We have all undoubtedly experienced a loss of electrical power in our office or our home. When this happens, even for a second, we typically find that we have to reset all of our digital alarm clocks. Let's assume that such a clock's internal digital hardware requires a current of 1 mA at a typical voltage level of 3.0 V, but the hardware will function properly down to 2.4 V. Under these assumptions, we wish to design a c irc uit that will 'hold" the voltage level for a short duration, for example, 1second. We know that the voltage across a capacitor cannot change instantaneously, and hence its use appears to be viable in this situation. Thus, we model this problem using the circuit in the figure below where the capacitor is employed to hold the voltage and the 1-rnA source represents the 1-mA load. Opens on power outages 1-mA load 3V As the circuit indicates, when the power fails, the capacitor must provide all the power for the digital hardware. The load, represented by the current source, will discharge the capacitor linearly. What should be the value of the capacitance to hold 2.4 volts for at least 1 s? || uF Answer must in numeral form, no decimal points, no units

We have all undoubtedly experienced a loss of electrical power in our office or our home. When this happens, even for a second, we typically find that we have to reset all of our digital alarm clocks. Let's assume that such a clock's internal digital hardware requires a current of 1 mA at a typical voltage level of 3.0 V, but the hardware will function properly down to 2.4 V. Under these assumptions, we wish to design a c irc uit that will 'hold" the voltage level for a short duration, for example, 1second. We know that the voltage across a capacitor cannot change instantaneously, and hence its use appears to be viable in this situation. Thus, we model this problem using the circuit in the figure below where the capacitor is employed to hold the voltage and the 1-rnA source represents the 1-mA load. Opens on power outages 1-mA load 3V As the circuit indicates, when the power fails, the capacitor must provide all the power for the digital hardware. The load, represented by the current source, will discharge the capacitor linearly. What should be the value of the capacitance to hold 2.4 volts for at least 1 s? || uF Answer must in numeral form, no decimal points, no units

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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We have all undoubtedly experienced a loss of electrical power in our office or our home. When this happens, even for a second, we typically find that we have to reset all of our digital alarm clocks. Let's assume that such a clock's internal digital hardware requires a current of 1 mA at a typical voltage level of 3.0 V, but the hardware will function properly down to 2.4 V. Under these assumptions, we wish to design a c irc uit that will 'hold" the voltage level for a short duration, for example, 1second. We know that the voltage across a capacitor cannot change instantaneously, and hence its use appears to be viable in this situation. Thus, we model this problem using the circuit in the figure below where the capacitor is employed to hold the voltage and the 1-rmA source represents the 1-mA load. Opens on power outages 1-mA load 3V As the circuit indicates, when the power fails, the capacitor must provide all the power for the digital hardware. The load, represented by the current source, will discharge the capacitor linearly. What should be the value of the capacitance to hold 2.4 volts for at least 1 s? uF Answer must in numeral form, no decimal points, no units
Transcribed Image Text:We have all undoubtedly experienced a loss of electrical power in our office or our home. When this happens, even for a second, we typically find that we have to reset all of our digital alarm clocks. Let's assume that such a clock's internal digital hardware requires a current of 1 mA at a typical voltage level of 3.0 V, but the hardware will function properly down to 2.4 V. Under these assumptions, we wish to design a c irc uit that will 'hold" the voltage level for a short duration, for example, 1second. We know that the voltage across a capacitor cannot change instantaneously, and hence its use appears to be viable in this situation. Thus, we model this problem using the circuit in the figure below where the capacitor is employed to hold the voltage and the 1-rmA source represents the 1-mA load. Opens on power outages 1-mA load 3V As the circuit indicates, when the power fails, the capacitor must provide all the power for the digital hardware. The load, represented by the current source, will discharge the capacitor linearly. What should be the value of the capacitance to hold 2.4 volts for at least 1 s? uF Answer must in numeral form, no decimal points, no units
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