Water falls down a vertical pipe by gravity alone. The flow between the vertical locations z1 and zz is fully developed, and velocity profiles at these two locations are sketched in the figure. Suppose the vertical pipe is now horizontal instead. In order to achieve the same volume flow rate as that of the vertical pipe, we must supply a forced pressure gradient. Calculate and choose the correct equation for the required pressure drop between two axial locations in the pipe that are the same distance apart as zz and z1. z = 72 z = z1 Multiple Choice P2 – PI = pg (z2 – z1)
Water falls down a vertical pipe by gravity alone. The flow between the vertical locations z1 and zz is fully developed, and velocity profiles at these two locations are sketched in the figure. Suppose the vertical pipe is now horizontal instead. In order to achieve the same volume flow rate as that of the vertical pipe, we must supply a forced pressure gradient. Calculate and choose the correct equation for the required pressure drop between two axial locations in the pipe that are the same distance apart as zz and z1. z = 72 z = z1 Multiple Choice P2 – PI = pg (z2 – z1)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![Water falls down a vertical pipe by gravity alone. The flow between the vertical locations z1 and zz is fully developed, and velocity profiles at these two
locations are sketched in the figure. Suppose the vertical pipe is now horizontal instead. In order to achieve the same volume flow rate as that of the
vertical pipe, we must supply a forced pressure gradient. Calculate and choose the correct equation for the required pressure drop between two axial
locations in the pipe that are the same distance apart as zz and z1.
z = 72
z = z1
Multiple Choice
P2 – PI = pg (z2 – z1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd757f313-7a88-4f54-9cb1-81cd05426a4a%2Fff47f30a-e371-458b-a714-b114957ae01c%2Fdj01z5r_processed.png&w=3840&q=75)
Transcribed Image Text:Water falls down a vertical pipe by gravity alone. The flow between the vertical locations z1 and zz is fully developed, and velocity profiles at these two
locations are sketched in the figure. Suppose the vertical pipe is now horizontal instead. In order to achieve the same volume flow rate as that of the
vertical pipe, we must supply a forced pressure gradient. Calculate and choose the correct equation for the required pressure drop between two axial
locations in the pipe that are the same distance apart as zz and z1.
z = 72
z = z1
Multiple Choice
P2 – PI = pg (z2 – z1)
![Multiple Choice
P2 – P1 = pg (z2 – 21)
P2 – P = pg (z2 + z1)
P2 – P = pg ()
P2 – P1 = pg (z2 × z1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd757f313-7a88-4f54-9cb1-81cd05426a4a%2Fff47f30a-e371-458b-a714-b114957ae01c%2F4uejlaa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Multiple Choice
P2 – P1 = pg (z2 – 21)
P2 – P = pg (z2 + z1)
P2 – P = pg ()
P2 – P1 = pg (z2 × z1)
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