Water can serve as both a nucleophile and a base. Given this information, predict the major product(s) of this reaction. water OH بھی میں ہی ہیں Ill only O IV only OI and II OI, II, and III OI and IV III and IV all will be formed equally ။ III IV

Mm.31. Subject  :- Chemistry

6. What is the major organic product generated in the reaction below? (A) CI OH (B) A.IOH C Cl₂ / H₂O (C) ||||C OH (D) OH CI

3. Predict the products of the following halogenation reactions. OH Br₂, hv HBr HBr ROOR PBr3

2-chloropropane is a major product of the reaction of chlorine with propane under ultraviolet light. Write the mechanism for this reaction including the initiation step and the two propagation steps.

H3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3

classify the following reaction  C2H6 + O2 -- CO2 + H2O

Predict the product(s) that forms and explain why it forms. NH₂ NH 1 eq. HBr

6. (Chapter 15-Q37) Indole is an aromatic heterocyclic that has a benzene ring fused to a pyrrole ring. Answer the following questions. Indole 6(a) What is the hybridization of N in this molecule? = 6(b) How many pi electrons N contributes to the ring? = 6() Which orbitals contribute to form a sigma bond between N and H in this molecule? = 6(c) What is the electronic relationship of Indole to naphthalene? Give the answer by comparing number of rings and number of pi electrons in both compounds, write x rings, y pi electrons=|

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