1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g) Given: 2 B(s) + 1/2O2(g) → B2O3(s) B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g) H2(g) + 1/2O2(g) → H₂O() H₂O(1)→ H₂O(g) AH₁ = -1273 kJ/mole AH₂=-2035 kJ/mole AH3= -286 kJ/mole 44 kJ/mole AH4=
1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g) Given: 2 B(s) + 1/2O2(g) → B2O3(s) B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g) H2(g) + 1/2O2(g) → H₂O() H₂O(1)→ H₂O(g) AH₁ = -1273 kJ/mole AH₂=-2035 kJ/mole AH3= -286 kJ/mole 44 kJ/mole AH4=
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g)
Given:
2 B(s) + 1/2O2(g) → B2O3(s)
B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g)
H2(g) + 1/2O2(g) → H₂O(1)
H₂O(1)→ H₂O(g)
AH₁ = -1273 kJ/mole
AH₂=-2035 kJ/mole
AH3= -286 kJ/mole
44 kJ/mole
AH4=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F981166fe-4516-4e5d-91f3-95cacb37d8bb%2F8fd1f43e-c5db-43e0-913e-4fae2da41362%2F7e62ubq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g)
Given:
2 B(s) + 1/2O2(g) → B2O3(s)
B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g)
H2(g) + 1/2O2(g) → H₂O(1)
H₂O(1)→ H₂O(g)
AH₁ = -1273 kJ/mole
AH₂=-2035 kJ/mole
AH3= -286 kJ/mole
44 kJ/mole
AH4=
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