1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g) Given: 2 B(s) + 1/2O2(g) → B2O3(s) B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g) H2(g) + 1/2O2(g) → H₂O() H₂O(1)→ H₂O(g) AH₁ = -1273 kJ/mole AH₂=-2035 kJ/mole AH3= -286 kJ/mole 44 kJ/mole AH4=

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1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g)
Given:
2 B(s) + 1/2O2(g) → B2O3(s)
B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g)
H2(g) + 1/2O2(g) → H₂O(1)
H₂O(1)→ H₂O(g)
AH₁ = -1273 kJ/mole
AH₂=-2035 kJ/mole
AH3= -286 kJ/mole
44 kJ/mole
AH4=
Transcribed Image Text:1) Find AH for the synthesis of B₂H6, diborane: 2B(s) + 3H2(g) → B₂H6(g) Given: 2 B(s) + 1/2O2(g) → B2O3(s) B₂H6(g) + 3 O2(g) →B2O3(s) + 3 H₂O(g) H2(g) + 1/2O2(g) → H₂O(1) H₂O(1)→ H₂O(g) AH₁ = -1273 kJ/mole AH₂=-2035 kJ/mole AH3= -286 kJ/mole 44 kJ/mole AH4=
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