Type it out instead of writing it please and thank you Watch the Introductory Video and Support Information on the upper left to learn how touse this virtual lab.i.i.Place a bottle of 0.1 M NaCl solution, the unknown AGNO, solution, a 250 mL Erlenmeyerflask, a 10 mL pipette, and a burette (in Glassware→Other) on the workbench. If thebench is said to be too full, set the items along the right side the bench to save space.Record the volume of the original unknown AGNO, solution in the Data sheet.Workbench 1Unknown AgNO,0.IMNaCI100 00 ml25s.0°C52.500 ml 25.0c250 ml Flask0000 ml25.OC10 ml Pipette00000 m 25.0c50 ml Burette0.0000 mt250cii.Transfer 50 mL of 0.1 M NaCl solution into the burette.Withdraw 10 mL of the unknown AGNO, solution into the pipette and transfer the solutioninto the empty Erlenmeyer flask.V.Deliver 1 mL of the 0.1 M NaCl solution from the burette into the 10 mL unknown AGNO,solution. Pay attention to mass of AgCl displayed in the information windowInformationName 250 m FlakVolume 11007mSpecies (s)ams00143310 m PotteTemperature 25.00c0000e5oon ANo,s0025.0CPredset 7.00From 50 m Bute to o mPa100 m antened250m Flask110075ocso00025ocRepeat addition of 1 mL of the 0.1 M NaCl solution from the burette into the unknownsolution until the mass of AgCl doesn't change any more. Record the mass of theprecipitate A9CI on the Data Sheet.vi. Volume of the original unknown AGNO3 solution =.mLMass of AGCI (s) =Mole of AgCl =(mole = mass /molar mass)Calculate mole of AGNO, in the 10 mL unknown solution based on the following reactionequation:NaCl) + AGNO(a0) → NANOS(a) + AgCla)Mole of AGNO, in the 10 mL unknown solution =use the coefficient ratio)_(hint,Mass of AGNO, in the 10 mL unknown solution =_(mass = mole x molar mass)Calculate mass of AGNO, in the original unknown solution as follows:Mass of AGNO, in the original unknown solutionvolume of the unknown AgN03 solution in mL= Mass of AGNO, in the 10 mL unknown solution x10 mL

From data Molar mass of AgNO3 = 169.87 g/mol Molar mass of AgCl = 143.32 g/mol

Volume of the original unknown AGNO3 solution = mL Mass of AgCI (s) = Mole of AgCl = - (mole = mass /molar mass) Calculate mole of AGNO, in the 10 mL unknown solution based on the following reaction equation: NaClo) + AGNOS() → NaNOyag) + AgCla) Mole of AGNO, in the 10 mL unknown solution = use the coefficient ratio) _(hint, Mass of AGNO, in the 10 mL unknown solution = (mass = mole x molar mass) Calculate mass of AGNO, in the original unknown solution as follows: Mass of AGNO, in the original unknown solution = Mass of AgNO3 in the 10 mL unknown solution x volume of the unknown A£N03 solution in mL 10 ml

Volume of the original unknown AGNO3 solution = mL Mass of AgCI (s) = Mole of AgCl = - (mole = mass /molar mass) Calculate mole of AGNO, in the 10 mL unknown solution based on the following reaction equation: NaClo) + AGNOS() → NaNOyag) + AgCla) Mole of AGNO, in the 10 mL unknown solution = use the coefficient ratio) _(hint, Mass of AGNO, in the 10 mL unknown solution = (mass = mole x molar mass) Calculate mass of AGNO, in the original unknown solution as follows: Mass of AGNO, in the original unknown solution = Mass of AgNO3 in the 10 mL unknown solution x volume of the unknown A£N03 solution in mL 10 ml

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Calculate the sum of coefficients for the following equation balanced for acidic conditions. 2+ XO7 + Y₂²+ → YO₂¹- + X²- Screen reader User: XO7 1 minus + Y₂ 2+ Answer: 25 × (149) YO₂ 1 minus + x2 minus
I know you don't answer graded questions and I am not looking for you to straight up give me the answer to this but how do I even start? like I said before I know that the highest peak is 16amu which is Oxygen but do I just the vertical bar as a ratio? Like the next bar to the left (15amu?) is like 90% intensity? so like 9:10 ratio? There isn't even a 15amu element so please just give me some idea where to start. The place in the book it tells you to go to read has nothing about this stuff, its about finding empirical formulas from mass or percentages.... please help me!
i need help solving this step by step with all the calculations Below is a set of absorbance data that you have obtained while doing an experiment studying the diffusion of potassium permanganate into solutions of water. This diffusion experiment was conducted at three temperatures. I need help to Calculate the diffusion rates for each of these temperature conditions. Time (min) 4°C 22°C 37°C 0 0.024 0.108 0.081 5 0.048 0.144 0.221 10 0.069 0.196 0.321 15 0.088 0.224 0.424 20 0.086 0.234 0.580 25 0.089 0.248 0.683 Once you calculate your diffusion rates in standard notation and use 3 digits past the decimal point (Note that the last zero is considered to be a digit) Diffusion Rate 4°C = __________________ Diffusion Rate 22°C = _________________ Diffusion Rate 37°C = _________________ To show how you calculated the diffusion rates for these temperature - What absorbance values did you choose to…
What defects are present in this picture
Malleability refers to the property of a metal to O be hammered into sheets O be drawn into wire O conduct heat resist breaking under tension
what segment represents contersation? oF E Tempera ture > IMF
“Adsorbents in finely divided form are more effective.” Why?
Which of the following separation methods can be used to separate stones from water O Centrifugation Extraction O Decantation Re-Crystallization
Stationary phase/s that can be used for both HILIC and NPLC Diol Cyano Unmodified silica Phenyl-bonded
Question 3 To Vacuum Pump Substrate Deposition of thin film Vaporized material Vaporized material Target material Evaporator Heater Target material Substrate Magnet To Vacuum Pump Electron beam Electron gun (a) Identify the two Physical Vapor Deposition Techniques in relation to the figure. (b) Why is a vacuum pump needed to achieve the deposition of the thin film?
Graphene, is a sheet of pure carbon with a thickness of 0.335nm. How many layers of graphene will be required to make 0.2 cm thick sheet? (1nm = 1x and 100cm =1m) A) 5.97 x 10^6 B) 5.97 x 10^7 C) 1.68 x10^6 D) 1.68 x10^7 E) 3.35 x10^6