There are two parts to this question. I need to know how many times fainter Venus is from a distance of 6 pc and what the apparent magnitude would be as well! Thank you!! **Problem Statement:**Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 6 pc? Assume Venus has the same illumination phase from your new vantage point. *(Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 × 10^5 AU).***Questions:**1. _____ times fainter2. What would its apparent magnitude be?---There are no graphs or diagrams in the image.

Apparent magnitude is the function of intensity that could be measured on Earth. Apparent magnitude…

Answered: Venus can be as bright as apparent…

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I have submitted this question 4 times and the responses have all been wrong. Please put your best person on this. I have tried 19.9923, 20.6, and 20.69 for part 1 and those are all wrong and I have tried 14.1122, 14.80, 8.41781, and 14.87 for part 2 and those are all wrong too. Please help! I'm wasting questions!
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