As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.

As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.

Similar questions

The sun of galaxy X has a diameter of about 796,000 mi with a maximum distance from Planet X's surface of about 78,700,000 mi. Planet X's moon has a diameter of 2,731 mi. For a total solar eclipse to occur, the moon must pass between the sun and Planet X. The moon must also be close enough to Planet X for the moon's umbra (shadow) to reach the surface of Planet X. The maximum distance that the moon can be from Planet X and still have a total solar eclipse occur i (Round to the nearest thousand as needed )
The Earth is shown with the equator marked. Another circle is marked that corresponds to a latitude λλ, which lies in the plane that is parallel to the equator.
The International Space Station (ISS) orbits the Earth once every 7.34 hours. If the radius of the Earth is 3,958.8 miles and the mass of earth is 5.972 x 10 24 kg, calculate the altitude of the ISS above the surface of the Earth, in miles. Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Keep at least on digit after the decimal point.
The International Space Station (ISS) orbits the Earth once every 7.2 hours. If the radius of the Earth is 3,958.8 miles and the mass of earth is 5.972 x 10 kg, calculate the altitude of the ISS above the surface of the Earth, in miles. Use G=6.674 x 10 11 Nm2/kg?. Write your answer in pure numbers, for example, 4567.8. Keep at least on digit after the decimal point. 24
I have submitted this question 4 times and the responses have all been wrong. Please put your best person on this. I have tried 19.9923, 20.6, and 20.69 for part 1 and those are all wrong and I have tried 14.1122, 14.80, 8.41781, and 14.87 for part 2 and those are all wrong too. Please help! I'm wasting questions!
On August 27, 2003, the planet Mars was at a distance of 0.373 AU from Earth. The diameter of Mars is 6788 km. Calculate the angular diameter of Mars, as seen from Earth on August 27, 2003. Give your answer in arcminutes.
When solving for something in an equation, for example if I was solving for "a" in this equation: x=v0^2 + 1/2at^2 (kinematic equation) I've seen it reduced and rearranged to look like: a = 2x/t^2 My question is why did 1/2 become 2 and why did it go to the numerator and not stay next to t^2 on the denominator?
How many orders of magnitude do you need to grow in spatial scale (size) to form a planet? Let's take the extreme ends of this scale, from a dust particle of radius a = 10-6m to the gas giant Jupiter (you can round up its radius to the nearest ten to keep it simple). What else has this difference in order of magnitude? Maybe pick something that's not a length scale. Be creative!
Calculate the angle a person needs to lean from the vertical when 1. walking a 14 m (radius) circular track at 22 mins per mile, and Enter to 2 significant figures Angle with respect to the vertical = = 0.85 ! No, that's not the correct answer. O 2. running at 4 min per mile. Enter to 2 significant figures Angle with respect to the vertical = 6.8 Use 1 mile = 1609.4 m Sense-making: Do your results for the leaning angle during walking agree with your observations about people walking on circular tracks? O
Kepler's 1st law says that our Solar System's planets orbit in ellipses around the Sun where the closest distance to the Sun is called perihelion. Suppose I tell you that there is a planet with a perihelion distance of 2 AU and a semi-major axis of 1.5 AU. Does this make physical sense? Explain why or why not.
The radius of the Earth is 6,400 km. What speed and direction would you have to travel along the equator to make the sun appear fixed in the sky is most nearly which of the following?
Map scales may be presented as a ratio, or as a bar on which distances are measured. A ratio of 1:50,000 means that every inch on the map represents 50,000 inches on the ground. If a has a scale where 1 inch represents 1 mile, what would be the scale expressed as a map ratio? (Hint: you need to calculate how many inches are in a mile) 1: On the bar below, how many miles are represented by 1 inch? miles What is this scale expressed as a ratio? 1: What is the value of point 'X'? 10 X 20 Scale (miles)