VAA + VB B+vcCvDD+ VEE + VFF
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Python /jupyter notebooks
Build the reaction
(kindly find reaction in the attached image)
The coefficient values are given:
vA = 1.7
vB = 2.1
vC = 1.5
vD = 3
vE = 3.8
vF = 1.2
The solution of your code should look like :
r0 : 1.7 A + 2.1 B + 1.5 C <=> 3 D + 3.8 E + 1.2 F
n_reactions = 1
Step by step
Solved in 2 steps with 1 images
- Asap design it with code Thank youfunc: sq: ADD X20, XZR, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X0, #0x0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 MUL x0, x0, x0 BR LR Assume the .text segment begins at address Ox00000000, and that the linker placed "sq" immediately after func in memory. Complete the following table (remove all leading Os and report your answer in hex): Absolute address of the function sq: Ox Byte offset of the first BL call: 0x 30 Byte offset of the second BL call: 0x 60 Byte offset of the third BL call: Ox ⁹⁰Two's Complement Adder/Subtractor1. Design a 4-bit Adder 2. Modify the Circuit for Addition and Subtraction 3. Create and Use Macros1. Using four instances of a full adder circuit (which you will create and save as a macro), design a circuit that can add two 4-bit binary numbers A and B. These 4-bit numbers are represented as a3 a2 a1 a0 and b3 b2 b1 b0, respectively, and the result of the addition will be represented as s3 s2 s1 s0. You are required to enter this circuit into a digital logic simulation tool (e.g., Digital Works) and verify that it correctly adds two 4-bit binary numbers.2. Modify the 4-bit adder circuit to include a mode input M. When M = 0, the circuit should perform addition (A + B), and when M = 1, it should perform subtraction (A - B). This modification should involve introducing suitable logic gates to handle subtraction3. You are expected to create a black box (macro) for the 1-bit full adder circuit and save it for future use. The instructions in the lab…
- 4. F(A,B,C ,D) =B'CD' + ABC'D + AB + A'BCD 5. F(W,X,Y,Z ) =W'X'YZ' + W'X + Y'Z'Define conversion time.C++ Program: Make a program that would demonstrate the concept of Line Coding: Polar NRZ: Remember: if next bit is 1, there is inversion if next bit is 0, no inversion neg – means the signal is in the negative axis pos – means the signal is in the positive axis inv – means there is inversion no inv – means there is no inversion a. initially high (starts with positive, inverse is negative) Input: 1 1 1 0 0 1 0 1 1 0 0 0 Output: inv neg inv pos inv neg no inv neg no inv neg inv pos no inv pos inv neg inv pos no inv pos no inv pos no inv pos b. initially low (starts with negative, inverse is positive) Input: 1 1 1 0 0 1 0 1 1 0 0 0 Output: inv pos inv neg inv pos no inv pos no inv pos inv neg no inv neg inv pos inv neg no inv neg no inv neg no inv neg The logic here is when input is 1, next inputted 1 will be inverse…
- Change dr IV SS to grmov r0, # 6Ah mov psw, # 00h 018 ric a 180100564-871598836 598836 b190100564871598836. 71598830 The final value of b190100567 1598836 2871698836 The accumulator's final value is not twice the 22h. 598636 00100504-9815883A PLI program has variables U, V, w, X, Y, Z which are declared as follows: DCL U BIT(4) W CHAR(5) Y CHAR(3) V FIXED (4,1). X FLOAT(4), Z FIXED(3): The Data Card for the same program contains the following information: U ='1101'B, V = 981-2; U='1101'B, V= 123•4, W = '123•4', X= 1052E + 02, Y= 'PQR', Z=- 249; a) Show what will be entered into memory storage in the computer as a result of the statements: GET DATA; followed a little later in the program by the statement: GET DATA(Z,V,W,YU,X); b) In the same program at a later stage, the contents of the memory locations corresponding to U, V, W, X, Y and Z were changed to 0100 769.2 144.7 •0129E – 03 BOG - 47 respectively. Show what will be printed out by the following statements: PUT DATA(U,Y); PUT SKIP DATA(X): PUT SKIP DATA(W,V,Z);