Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H₂S(g) + 302(g) → 2H₂O(g) + 2SO2(g) AH (H₂S(g)) = - AH (O₂(g)) = 0.0 kJ/mol AH (H₂O(g)) = AH° rxn = AH (SO₂ (9)) = ANSWER: Species AH (kl/mol) H₂(g) SO₂(9) H₂S(g) Using standard heats of formation, calculate the standard enthalpy change for the following reaction. C(s,graphite) + O₂(g) CO₂(g) 0.0 -296.8 -20.6 = -20.6 kJ/mol kJ kJ = -241.8 kJ/mol A scientist measures the standard enthalpy change for the following reaction to be 316.2 kJ: H₂S(g) + 2H₂O(1)→ 3H₂(g) + SO₂(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H₂O(l) is -824.2 0.0 0.0 Substance AH (kJ/mol) Fe₂O3 (8) H₂(g) Fe(s) = -296.8 kJ/mol A scientist measures the standard enthalpy change for the following reaction to be 76.3 kJ: Fe₂O3 (8) + 3H₂(g) → 2Fe(s) + 3H₂O(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H₂O(g) is kJ/mol. kJ/mol.

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Question:
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
2H₂S(g) + 302(g) → 2H₂O(g) +2SO2(g)
AH (H₂S(g)) = -20.6 kJ/mol
AH (O₂(g)) = 0.0 kJ/mol
AH (H₂O(g)) = = -241.8 kJ/mol
AH (SO₂(g)) = -296.8 kJ/mol
AHº =
rxn
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
C(s,graphite) + O₂(g)—CO₂(g)
ANSWER:
Species AH (kJ/mol)
0.0
H₂(g)
SO₂(g) -296.8
H₂S(g)
-20.6
kJ
A scientist measures the standard enthalpy change for the following reaction to be 316.2 kJ:
H₂S(g) + 2H₂O(1)→ 3H₂(g) + SO₂(g)
Based on this value and the standard enthalpies f formation for the other substances, the standard enthalpy of formation of H₂O(l) is
kJ
A scientist measures the standard enthalpy change for the following reaction to be 76.3 kJ:
Fe₂O3(s) + 3H₂(g) → 2Fe(s) + 3H₂O(g)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H₂O(g) is
-824.2
0.0
Substance AH (kJ/mol)
Fe₂O3 (8)
H₂(g)
Fe(s)
0.0
kJ/mol.
kJ/mol.
Transcribed Image Text:Question: Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H₂S(g) + 302(g) → 2H₂O(g) +2SO2(g) AH (H₂S(g)) = -20.6 kJ/mol AH (O₂(g)) = 0.0 kJ/mol AH (H₂O(g)) = = -241.8 kJ/mol AH (SO₂(g)) = -296.8 kJ/mol AHº = rxn Using standard heats of formation, calculate the standard enthalpy change for the following reaction. C(s,graphite) + O₂(g)—CO₂(g) ANSWER: Species AH (kJ/mol) 0.0 H₂(g) SO₂(g) -296.8 H₂S(g) -20.6 kJ A scientist measures the standard enthalpy change for the following reaction to be 316.2 kJ: H₂S(g) + 2H₂O(1)→ 3H₂(g) + SO₂(g) Based on this value and the standard enthalpies f formation for the other substances, the standard enthalpy of formation of H₂O(l) is kJ A scientist measures the standard enthalpy change for the following reaction to be 76.3 kJ: Fe₂O3(s) + 3H₂(g) → 2Fe(s) + 3H₂O(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H₂O(g) is -824.2 0.0 Substance AH (kJ/mol) Fe₂O3 (8) H₂(g) Fe(s) 0.0 kJ/mol. kJ/mol.
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