Use the standard linked list below to answer True/False statements 9-12: 8 10 7 4 null 9) The "head" pointer of this list is pointing to Node 4 10)If we called "insert(5)", the new node's "next" pointer will point to Node 8

Use the standard linked list below to answer True/False statements 9-12: 8 10 7 4 null 9) The "head" pointer of this list is pointing to Node 4 10)If we called "insert(5)", the new node's "next" pointer will point to Node 8

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Recursive Multiplication Given an JavaScript object list of books that each have a pages attribute to define the number of pages in the book, find the product of all the pages in the object list of books using recursion (you must use recursion to solve this problem). Keep in mind: The input list object may be completely empty (ex. {}) The next attribute may not be defined function getPageCount(list) {// your code here// returns an integer}Example test case:Input: {"book":"A","pages":1,"next":{"book":"B","pages":2,"next":{"book":"C","pages":3,"next": null}}}Output: 6Reasoning: 1 * 2 * 3 pages
How nodes are defined (struct node (value count left right) #:mutable #:transparent) Write in Racket (traverse n) A traversal of a BST is an algorithm for “visiting” all node in the BST. The traversal must visit each node exactly once. In the case of a linked list, a traversal is trivial since the structure is linear: start at the head, move to the next node, and stop when you reach the tail. In the case of a BST, traversal must account for multiple child nodes and keep track of which subtrees have already been visited and which have not. There are three types of traversal: in-order, pre-order, and post-order. We will only implement in-order. The in-order traversal of a BST has the property that the node values will display in ascending or sorted order. The function can be defined either recursively or iteratively. Recursion is much simpler, so we’ll stick to that. Recursive Algorithm for In-Order Traversal of BST parameter: node n, the root of the tree…
struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };
Select true or false for the statements below. Explain your answers if you like to receive partial credit 4) Given a stack implemented as a standard linked list (only a head pointer) with O(1)push and O(1) pop, and the following functions are performed in sequence:Push(“Charmander”), Push(“Squirtle”), Push(“Bulbasaur”), Pop(), Push(“Larvitar”),Push(“Eevee”), Pop(), Pop()Which of the following is true after all the functions are executed?a. Charmander and Squirtle will be the only elements left on the stackb. The head node will be pointing to Charmanderc. If you Push(“Pikachu”), it will be the last node of the linked list
True/False Select true or false for the statements below. Explain your answers if you like to receive partial credit. 3) Which of the following is true about the insertBeforeCurrent function for a CircularLinked List (CLL) like you did in programming exercise 1?a. If the CLL is empty, you need to create the new node, set it to current, andhave its next pointer refer to itselfb. The worst case performance of the function is O(n)c. If you insert a new element with the same data value as the current node, theperformance improves to O(log n)
C++
#include <iostream> using namespace std; #define SIZE 5 //creating the queue using array int A[SIZE]; int front = -1; int rear = -1; //function to check if the queue is empty bool isempty() { if(front == -1 && rear == -1) return true; else return false; } //function to enter elements in queue void enqueue ( int value ) { //if queue is full if ((rear + 1)%SIZE == front) cout<<"Queue is full \n"; else { //now the first element is inserted if( front == -1) front = 0; //inserting element at rear end rear = (rear+1)%SIZE; A[rear] = value; } } //function to remove elements from queue void dequeue ( ) { if( isempty() ) cout<<"Queue is empty\n"; else //only one element if( front == rear ) front = rear = -1; else front = ( front + 1)%SIZE; } //function to show the element at front void showfront() { if( isempty()) cout<<"Queue is empty\n"; else cout<<"element at front is:"<<A[front]; } //function to display the queue void…
7. display a value at a specified index in a linked chain of integers For example, display the 3rd element in the chain, display the 10th element in the chain, etc. a.O(log n) b.O(n2) c.O(n) d.O(1) e.none of these is correct
True or False For each statement below, indicate whether you think it is True or False. If you like, you can provide a description of your answer for partial credit in case you are incorrect. Use the standard linked list below to answer True/False statements 9-12: 8 7 null 4 10 The “head” pointer of this list is pointing to Node 4 If we called “insert(5)”, the new node’s “next” pointer will point to Node 8 If we called “delete(10)”, Node 7’s “next” pointer will point to Node 8 If we called “search(20)”, the “head” pointer will be at Node 4 after the search function ends
Write a function with the signature below that returns the sum of the last k elements of a singly linked list that contains integers. int returnSumOfLastKNodes(Node* head, int k) Example: 10 -> 5->8->15->11->9->23 10 represents the head node, returnSumOfLastKNodes(Node* head, 4) will return 58.
Write C++ code to display all even numbers in the a doubly linked list pointed to by Dlist. Use while loop to scan all nodes from the start to the end. (Each node has three fields: a data field that contains the information, and right and left fields contain pointers to nodes on either side. Ex. p->left represents the address of the node to the left of node p) (any number of nodes in the linked list) Dlist 4 3 8 HIIN 7 1