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- A weight-loss program wants to test how well their program is working. The company selects a simple random sample of 51 individual that have been using their program for 15 months. For each individual person, the company records the individual's weight when they started the program 15 months ago as an x-value. The subject's current weight is recorded as a y-value. Therefore, a data point such as (205, 190) would be for a specific person and it would indicate that the individual started the program weighing 205 pounds and currently weighs 190 pounds. In other words, they lost 15 pounds. When the company performed a regression analysis, they found a correlation coefficient of r = 0.707. This clearly shows there is strong correlation, which got the company excited. However, when they showed their data to a statistics professor, the professor pointed out that correlation was not the right tool to show that their program was effective. Correlation will NOT show whether or not there is…A study done in 1997 showed that 4.2% of mothers smoked cigarettes during their pregnancy. An obstetrician feels that this percentage is higher now. To test this, the obstetrician takes a sample of 200 mothers and finds that 10 of them smoked during their pregnancy. Test the obstetrician's claim at the a=0.05 level of significance. Write your answer in the following form P-Value, Conclusion Example: 0.15, There is not sufficient evidence that the mean weight of pandas is less than 200 pounds. Edit View Insert Format Tools Table 12pt v Paragraph v BIUA e T?u 画① O words ņ V12 96 5n SO F H. B N2man loves, as everyone should, to collect and analyze statistical information. He wishes to find a relationship between how many hours students study and how they do on their statistics tests. He takes a random sample of 16 students at Ideal U., asks how many hours they studied for a university-wide stat test and how they did on the test, enters the data into a computer for analysis and presents the results below. ANALYSIS OF HOURS AND GRADES (n = 16): Descriptive Statistics: HOURS GRADES Mean: 4.2 75.8 Mode: 5.0 79.0 St. Dev: 2.3 10.1 Quartiles: Q0 2.0 34.0 Q1 3.2 53.7 Q2 4.7 78.5 Q3 6.3 86.9 Q4 9.0 97.0 Regression Analysis: Reg. Eq. is: GRADE = 16.9 + 9.025*HOURS Rsquared = .985 std error = 0.027 F = 8.52 p = .018 What problem might there be in using the regression model to predict what grade a student might get if they studied 10 hours? a. The predicted grade for 10 hours is more than 100, which is impossible. b. The value of 10…
- Consider data on every game played by the Brooklyn Nets in 2014 (82 games) that includes the variables margin, - the Net's margin of victory (number of points the Nets scored minus the number of points their opponent scored) for game i, and • home; - a dummy variable equal to 1 when the Nets are the home team (game i was played in their home arena) and equal to 0 when they are the away team (game i was played in the opponent's arena). I use the least-squares method to estimate the following regression model margin = a + ßhome; + ei Below is the Stata output corresponding to the estimated regression line: regress margin home if team===== "Brooklyn Nets" . Source Model Residual Total margin home _cons SS 1459.95122 15252.0488 16712 df 1459.95122 1 80 190.65061 None of the above 81 206.320988 Coef. Std. Err. 8.439024 3.049595 -5.219512 2.156389 MS t Number of obs F(1, 80) Prob > F R-squared O The Nets lost more games than they won in 2014 P>|t| 2.77 0.007 -2.42 0.018 Adj R-squared = Root…I need #4 answeredA pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples of rats are selected with n=9 in each sample.The first sample receives the drug every day. The second sample is given the drug once a week, and the third sample receives no drug at all (the control group). These assignments of drugs are called treatments.The (dependent) variable being compared is the amount of food eaten by each rat over a 1-month period. These data are analyzed by an ANOVA, and the results are reported in the following summary table. How many groups (or population means or treatments) are being compared in this problem? _________ (Enter a whole number) What is the total number of data used in this problem? _________(Enter a whole number) Fill in all missing values in the table. (Hint: Start with the df column and your above answers.)If there are decimal places in your answer, provide 2 or more decimal places. Source of Variation SS df MS F…
- I HAVE THE GRAND MEAN ALREADY NEED REST OF THE PROBLEMS SOLVED. ANOVA. Dr. Milgram is conducting a patient satisfaction survey, rating how well her patients like her on a scale of 1-10. Her patients tend to fall into three categories: “Like a lot”, “like somewhat”, and “dislike a lot”. She believes that she might get different satisfaction scores from people in each group, but (because she's not great at numbers) she wants you to do an ANOVA to be sure. She has collected data from 12 patients (three equal groups) with the following results. Group 1) “Like a lot” Mean: 8 SS: 2 N: df: Group 2) “Like somewhat” Mean: 5 SS: 6 N: df: Group 3) “Dislike a lot” Mean: 2 SS: 4 N: df: Grand Mean: 4 df Within-Group:__________ df Between-Groups:___________ Estimated Variance (S21) for Group 1:…Q1. A psychologist conducted a study on the relationship between introversion and shyness. The values are results for scales of introversion and shyness. High positive scores on each scale indicate high introversion or shyness; and high negative scores indicate low introversion or shyness. Data collected from 10 people as follows: Introversion 4 -7 -1 0 6 7 -4 -9 -5 8 Shyness 11 -7 -1 -3 0 7 -1 -8 -1 5 a) Compute the correlation coefficient relating introversion and shyness scores. b) Find the regression equation which predicts introversion from shyness. c) What introversion score would you predict from a shyness score of 7?You wish to test the following claim (Ha) at a significance level of a = 0.02. For the context of this problem, d PostTest – PreTest where the first data set represents a pre-test and the second data set represents a post-test. (Each row represents the pre and post test scores for an individual. Be careful when you enter your data and specify what your x1 and x2 are so that the differences are computed correctly.) H.: Hd Ha: Hd + 0 %3| You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: pre-test post-test 50.8 42.8 57.6 46.5 59.5 52.9 62.4 49.2 57.5 55.8 52.3 54.3 62.2 49.7 58.5 56.7 61.1 60.3 60.8 54.5 65.1 64 62.9 59 55.9 49.3 60.9 51.1 64.4 62.9 50.8 41.3 59 56.4 56.1 49 66 54 60.1 52.9 62.1 59.9 55.6 46.8 56.5 53 60.3 55 55 48.4 What is the test statistic for this sample? test statistic = (Report answer accurate to 4 decimal places.)
- The line of best fit through a set of data isy=21.974+1.021xy=21.974+1.021xAccording to this equation, what is the predicted value of the dependent variable when the independent variable has value 140? Y=A research report states t(18)=+3.00, p<. 05. For this test, r2 =. 33Consider data on every game played by the Brooklyn Nets in 2014 (82 games) that includes the variables margin; - the Net's margin of victory (number of points the Nets scored minus the number of points their opponent scored) for game i, and • home; - a dummy variable equal to 1 when the Nets are the home team (game i was played in their home arena) and equal to 0 when they are the away team (game i was played in the opponent's arena). I use the least-squares method to estimate the following regression model margin = a + ßhome; + ei Below is the Stata output corresponding to the estimated regression line: regress margin home if team==== "Brooklyn Nets" Source Model Residual Total margin home _cons SS 1459.95122 15252.0488 16712 df 1 80 Coef. Std. Err. MS 81 206.320988 8.439024 3.049595 -5.219512 2.156389 1459.95122 190.65061 t Number of obs F (1, 80) Prob > F R-squared. Adj R-squared = Root MSE P>|t| 2.77 0.007 -2.42 0.018 82 7.66 0.0070 0.0874 0.0760 13.808 [95% Conf. Interval]…