Use the References to access important values if needed for this question. The freezing point of water is 0.00°C at 1 atmosphere. How many grams of aluminum sulfate (342.2 g/mol), must be dissolved in 275.0 grams of water to reduce the freezing point by 0.350°C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula KB CC/m) Kr(°C/m) Water H20 0.512 1.86 Ethanol CH;CH2OH 1.22 1.99 Chloroform CHCI; 3.67 Benzene CH6 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 g aluminum sulfate. Submit Answer Retry Entire Group 8 more group attempts remaining
Use the References to access important values if needed for this question. The freezing point of water is 0.00°C at 1 atmosphere. How many grams of aluminum sulfate (342.2 g/mol), must be dissolved in 275.0 grams of water to reduce the freezing point by 0.350°C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula KB CC/m) Kr(°C/m) Water H20 0.512 1.86 Ethanol CH;CH2OH 1.22 1.99 Chloroform CHCI; 3.67 Benzene CH6 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 g aluminum sulfate. Submit Answer Retry Entire Group 8 more group attempts remaining
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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 alt="Use the References to access important values if needed for this question.
The freezing point of water is 0.00°C at 1 atmosphere.
How many grams of aluminum sulfate (342.2 g/mol), must be dissolved in 275.0 grams of water to reduce the freezing point by 0.350°C ? Refer to the
table for the necessary boiling or freezing point constant.
Solvent
Formula
K, (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH;CH,OH
1.22
1.99
Chloroform
CHCI3
3.67
Benzene
C6H6
2,53
5.12
Diethyl ether CH3CH,OCH,CH;
2,02
g aluminum sulfate
Submit Answer
Retry Entire Group
8 more group attempts remaining
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Transcribed Image Text:Use the References to access important values if needed for this question.
The freezing point of water is 0.00°C at 1 atmosphere.
How many grams of aluminum sulfate (342.2 g/mol), must be dissolved in 275.0 grams of water to reduce the freezing point by 0.350°C ? Refer to the
table for the necessary boiling or freezing point constant.
Solvent
Formula
K, (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH;CH,OH
1.22
1.99
Chloroform
CHCI3
3.67
Benzene
C6H6
2,53
5.12
Diethyl ether CH3CH,OCH,CH;
2,02
g aluminum sulfate
Submit Answer
Retry Entire Group
8 more group attempts remaining
(Previous
Next
Email Instructor
Save and Exit
Cengage Learning | Cengage Technical Support
MacBook Air
888
こ。
DII
DD
Fア
FO
F10
F11
F12
&
4
5
(
)
6
8
9
%3D
delete
R
U
P
{
}
[
[
G
H
J
K
L
:
%3D
re
M
く
>
?
command
option
ピ
* 00
ト
Expert Solution

Step 1
The depression in freezing point is given by the formula :
ΔTf = i x kf x m
where, m = molality = w / (M xW)
Step by step
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