Use the normal distribution to find a confidence interval for a difference in proportions p₁Assume the results come from random samples.A 90% confidence interval for p₁ - p₂ given that p = 0.75 with n = 440 and p₂ = 0.65 with #₂ = 360Give the best estimate for p₁ - p₂, the margin of error, and the confidence interval.Round your answer for the best estimate to two decimal places and round your answers for the margin of error and the confidenceinterval to three decimal places.Best estimate: iMargin of error: iConfidence interval:- P₂ given the relevant sample results.to

Confidence level is First sample:Sample proportion Sample size Second sample:Sample proportion…

Answered: Use the normal distribution to find a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Use the normal distribution to find a confidence interval for a difference in proportions p¡ – P2 given the relevant sample results. Assume the results come from random samples. A 95% confidence interval for p, – pɔ given counts of 88 yes out of 120 sampled for Group 1 and 47 yes out 150 sampled for Group 2 Give the best estimate for p, - P2, the margin of error, and the confidence interval. Round your answers to three decimal places.
Please solve for the confidence interval and population standard deviation
A statistics class is estimating the mean height of all female students at their college. They collect a random sample of 42 female students and measure their heights. The mean of the sample is 65.3 inches and the sample standard deviation is 5.4 inches. Find the 90% confidence interval for the mean height of all female students in their school? Assume that the distribution of individual female heights at this school is approximately normal. 1. The t value is 1.3025 2. The standard error has a value of -- 3. The margin of error has a value of 4. Find the 90% confidence interval for the mean height of all female students in their school
Jose wants to advertise how many chocolate chips are in each Big Chip cookie at his bakery. He randomly selects a sample of 52 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 19.5. The population standard deviation is 2.5. What is the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Assume the data is from a normally distributed population.Round answers to 3 decimal places where possible.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 70 dates, the mean record high daily temperature in a certain city has a mean of 86.37°F Assume the population standard deviation is 14.38 F The 90% confidence interval is ( I) (Round to two decimal places as needed.) The 95% confidence interval is ( D (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below. The 90% confidence interval The 95% confidence interval Interpret the results. O A. You can be 90% confident that the population mean record high temperature is between the bounds of the 90% confidence interval, and 95% confident for the G50% intonial Click to select your answer(S). 180min ZoT oo
A random sample of n = 16 mid-sized cars tested for fuel consumption gave a mean of x ¯ = 21.69 miles per gallon with a standard deviation of s = 2.51 miles per gallon. Assuming that the miles per gallon given by all mid-sized cars have a normal distribution, find a 99 % confidence interval for the population mean, μ .Round your answers to two decimal places.
n=10 b = 0.50 sb = 0.02 α=0.05 find the confidence interval for β.
How many replicate measurements are necessary to decrease the 99% confidence limits for the analysis above by 50% of the confidence limits. Standard deviation is 0.0721, Mean is 2.43, there are 5 measurements and the z value is 2.58.
The random sample of n=75�=75 yielded a sample mean of x¯=26�¯=26.Assume that we know the population standard deviation is σ=30�=30. Step 2 of 3 : Calculate a 95% confidence interval for the population mean. Round your answers to 2 decimals places.
For a sample of 6 operating rooms taken in a hospital study, the mean noise level was 38.8 decibels and the standard deviation was 11.4 . Find the 90% confidence interval of the true mean of the noise levels in the operating rooms. Assume the variable is normally distributed. Round your answers to at least two decimal places. <<μ
The mean diastolic blood pressure for a random sample of 70 people was 84 millimeters of mercury. If the standard deviation of individual blood pressure readings is known to be 12 millimeters of mercury, find a 90% confidence interval for the true mean diastolic blood pressure of all people. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. upper limit ? lower limit?

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