A confidence interval for the difference of population means is calculated as the difference of the point estimates plus or minus the margin of error. A point estimate for the difference was found to be x₁ - x₂ = -1.4 so now the margin of error needs to be found. 2 The margin of error is calculated as follows where t ¹a/2 is the value of t that corresponds to an upper tail area of with a calculated degrees of freedom, s, is the sample standard deviation from population 1, n, is the sample size from population 1, S₂ is the sample standard deviation from population 2, and n, is the sample size from population 2. ta/2 √ 2 $1 01 + 2 $2 7₂ Before finding the margin of error, the values for t and the standard deviations for both samples must be found. a/2 2 The value of ta/2 can be found on a table, but the values for and the degrees of freedom are needed. Recall that a is found by setting the confidence level equal to (1 a) and solving for a. The margin of error for 90% confidence is to be found. Expressing 90% as a probability, gives 0.90, so we have 1 - α = 0.90. Therefore, a = a and = 2
A confidence interval for the difference of population means is calculated as the difference of the point estimates plus or minus the margin of error. A point estimate for the difference was found to be x₁ - x₂ = -1.4 so now the margin of error needs to be found. 2 The margin of error is calculated as follows where t ¹a/2 is the value of t that corresponds to an upper tail area of with a calculated degrees of freedom, s, is the sample standard deviation from population 1, n, is the sample size from population 1, S₂ is the sample standard deviation from population 2, and n, is the sample size from population 2. ta/2 √ 2 $1 01 + 2 $2 7₂ Before finding the margin of error, the values for t and the standard deviations for both samples must be found. a/2 2 The value of ta/2 can be found on a table, but the values for and the degrees of freedom are needed. Recall that a is found by setting the confidence level equal to (1 a) and solving for a. The margin of error for 90% confidence is to be found. Expressing 90% as a probability, gives 0.90, so we have 1 - α = 0.90. Therefore, a = a and = 2
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A confidence interval for the difference of population means is calculated as the difference of the point estimates plus or minus the
margin of error. A point estimate for the difference was found to be x₁ - x₂ = -1.4 so now the margin of error needs to be found.
2
The margin of error is calculated as follows where t is the value of t that corresponds to an upper tail area of a with a calculated
degrees of freedom, s, is the sample standard deviation from population 1, n, is the sample size from population 1, s2 is the sample
standard deviation from population 2, and n, is the sample size from population 2.
ta/2 √
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Before finding the margin of error, the values for t/2 and the standard deviations for both samples must be found.
α
2
The value of ta/2 can be found on a table, but the values for and the degrees of freedom are needed. Recall that a is found by
setting the confidence level equal to (1 a) and solving for a. The margin of error for 90% confidence is to be found. Expressing 90%
as a probability, gives 0.90, so we have 1 - a = 0.90. Therefore, a =
and
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S₂
2
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4
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2
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pulation means.
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4/14/2023
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