Find a number L such that P|L 95. %3D Hint: A useful fact when using tables to find F-values is that P(k s U\/U2) = P(U2/U1 < 1/k). Basically this says to find the F-value that represents L, we must reciprocate the sides and change the

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Chapter1: Combinatorial Analysis
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I am needing assistance with this problem. The question is
the part where it says "Find a number L".
Let S? denote the sample variance for a random sample of 10 In(LC50) values for copper and let S3
denote the sample variance for a random sample of 8 In(LC50) values for lead, both samples using the
same species of fish. The population variance for measurements on copper is assumed to be twice the
corresponding population variance for measurements on lead. Assume S? to be independent of S.
Find a number L such that PL<
= .95.
Hint: A useful fact when using tables to find F-values is that P(k s U\/U2) = P(U2/U1 s 1/k).
Basically this says to find the F-value that represents L, we must reciprocate the sides and change the
direction of the inequality because the F table only lists F-values for a s 0.1 in the upper tail. This L
value is on the lower side of the curve. Note that this also switches you numerator and denominator
degrees of freedom. If you use R this will be a non issue for you!
Transcribed Image Text:I am needing assistance with this problem. The question is the part where it says "Find a number L". Let S? denote the sample variance for a random sample of 10 In(LC50) values for copper and let S3 denote the sample variance for a random sample of 8 In(LC50) values for lead, both samples using the same species of fish. The population variance for measurements on copper is assumed to be twice the corresponding population variance for measurements on lead. Assume S? to be independent of S. Find a number L such that PL< = .95. Hint: A useful fact when using tables to find F-values is that P(k s U\/U2) = P(U2/U1 s 1/k). Basically this says to find the F-value that represents L, we must reciprocate the sides and change the direction of the inequality because the F table only lists F-values for a s 0.1 in the upper tail. This L value is on the lower side of the curve. Note that this also switches you numerator and denominator degrees of freedom. If you use R this will be a non issue for you!
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