Use the normal distribution to find a confidence interval for a difference in proportions P1 P2 given the relevant sample results.Assume the results come from random samples.A 95% confidence interval for p₁ - p2 given that p₁=Give the best estimate for p₁ - p2, the margin of error, and the confidence interval.Round your answer for the best estimate to two decimal places and round your answers for the margin of error and the confidenceinterval to three decimal places.Best estimate: i 0Margin of error: i 0Confidence interval: i0.79 with n₁ = 500 and p2 = 0.69 with n₂ = 2200to i 0

we have :- p̂1 = 0.79 p̂2 = 0.69 Now best estimate for confidence interval for difference in…

Answered: Use the normal distribution to find a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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find P-Value
the distribution of scores on a standardized test is approximately Normal with standard deviation of σ = 21. If a sample of 135 students had a mean score of x¯ = 73.6, use this to find a 99% confidence interval for the mean score of all students on this test. We are 99% confident that the the mean score of students on this test was in the interval ______ to _____. What is the margin of error for your confidence interval? Margin of error =
answer both parts please list z score an the intervals like mean and standard devation. test stastic fortmula with values the procedure name the parameter in c level context and if its random or normal
please solve
The lengths of pregnancies in a small rural village are normally distributed with a mean of 265 days and a standard deviation of 15 days. In what range would you expect to find the middle 50% of most pregnancies? Between and If you were to draw samples of size 58 from this population, in what range would you expect to find the middle 50% of most averages for the lengths of pregnancies in the sample? Between and Enter your answers as numbers. Your answers should be accurate to 1 decimal places.
A sample of n=20 scores has a mean of M=107. Find the z-score for this sample if it was obtained from a population with a mean of μ=109 and a standard deviation of σ=5. Group of answer choices +1.73 -1.79 +0.54 -0.87
Using this data set What is the standard error of the relevant distribution? Ignoring that the number of men in the 2012 Survey was about 17,675, and the number of women was about 18,634, assume the samples were 100 men and 100 women in each Survey My worked solution is: P1: men proportion change = 15.5/100 = 0.155 N1 = 100 P2: women proportion change = 57.9/100 = 0.579 N2 = 100 {[0.155 * (1 - 0.155) /] + [0.579 * (1 - 0.579) / 100]} = 0.0037 Standard Error = 0.0037 is this correct?
The mean amount of time it takes a kidney stone to pass is 15 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible. . Find the Inter Quartile Range (IQR) for IQ scores. Round your answers to 2 decimal places.Q1: Q3: IQR:

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