Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): cal/g °C J/g °C Substance Elements Aluminum, Al(s) Copper, Cu(s) Gold, Au(s) Iron, Fe(s) Silver, Ag(s) Titanium, Ti(s) Compounds Ammonia, NH,(g) Ethanol, C₂H₂OH(1) Sodium chloride, NaCl(s) Water, H₂O(1) Water, H₂O(s) Aluminum, Al(s) Copper, Cu(s) Gold, Au(s) Iron, Fe(s) Silver, Ag(s) Titanium, Ti(s) Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): Substance cal/g °C J/g °C Elements Water, H₂O(1) Water, H₂O(s) 0.214 0.0920 0.0308 0.108 0.0562 0.125 0.488 0.588 0.207 1.00 0.485 Substance Elements Aluminum, Al(s) Compounds Ammonia, NH₂(g) 0.488 Ethanol, C₂H₂OH(1) 0.588 Sodium chloride, NaCl(s) 0.207 1.00 0.485 Copper, Cu(s) Gold, Au(s) Iron, Fe(s) Silver, Ag(s) Titanium, Ti(s) Compounds Ammonia, NH3(g) Ethanol, C₂H₂OH(!) Sodium chloride, NaCl(s) Water, H₂O(1) Water, H₂O(s) 0.214 0.0920 0.0308 0.897 0.385 0.129 0.452 0.235 0.523 2.04 2.46 0.864 4.184 2.03 0.897 0.385 0.129 0.108 0.452 0.0562 0.235 0.125 0.523 Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): cal/g °C J/g °C 2.04 2.46 0.864 4.184 2.03 0.897 0.214 0.0920 0.385 0.0308 0.129 0.108 0.452 0.0562 0.235 0.125 0.523 0.488 2.04 0.588 2.46 0,207 0.864 1.00 4.184 0.485 2.03 Part A to heat 6.15 g of water from 5.5°C to 69.4 °C – ΑΣΦΑ Part B Submit Previous Answers Request Answer X Incorrect; Try Again ▼ to heat 6.15 g of water from 5.5°C to 69.4 °C - ΑΣΦ 3 Part C ID ΑΣΦ Submit ▼ Part D lost when 75.6 g of water cools from 86.4° C to 3.6 °C |Ε| ΑΣΦ Part E Request Answer to heat 12.2 g of silver from 112° C to 295 °C lost when 75.6 g of water cools from 86.4° C to 3.6 °C ID ΑΣΦ Submit Part F ? Request Answer to heat 12.2 g of silver from 112° C to 295 °C ? IVE ΑΣΦ ? J ? ? ? J cal J cal
Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): cal/g °C J/g °C Substance Elements Aluminum, Al(s) Copper, Cu(s) Gold, Au(s) Iron, Fe(s) Silver, Ag(s) Titanium, Ti(s) Compounds Ammonia, NH,(g) Ethanol, C₂H₂OH(1) Sodium chloride, NaCl(s) Water, H₂O(1) Water, H₂O(s) Aluminum, Al(s) Copper, Cu(s) Gold, Au(s) Iron, Fe(s) Silver, Ag(s) Titanium, Ti(s) Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): Substance cal/g °C J/g °C Elements Water, H₂O(1) Water, H₂O(s) 0.214 0.0920 0.0308 0.108 0.0562 0.125 0.488 0.588 0.207 1.00 0.485 Substance Elements Aluminum, Al(s) Compounds Ammonia, NH₂(g) 0.488 Ethanol, C₂H₂OH(1) 0.588 Sodium chloride, NaCl(s) 0.207 1.00 0.485 Copper, Cu(s) Gold, Au(s) Iron, Fe(s) Silver, Ag(s) Titanium, Ti(s) Compounds Ammonia, NH3(g) Ethanol, C₂H₂OH(!) Sodium chloride, NaCl(s) Water, H₂O(1) Water, H₂O(s) 0.214 0.0920 0.0308 0.897 0.385 0.129 0.452 0.235 0.523 2.04 2.46 0.864 4.184 2.03 0.897 0.385 0.129 0.108 0.452 0.0562 0.235 0.125 0.523 Use the heat equation to calculate the energy, in joules and calories, for each of the following (see the table): cal/g °C J/g °C 2.04 2.46 0.864 4.184 2.03 0.897 0.214 0.0920 0.385 0.0308 0.129 0.108 0.452 0.0562 0.235 0.125 0.523 0.488 2.04 0.588 2.46 0,207 0.864 1.00 4.184 0.485 2.03 Part A to heat 6.15 g of water from 5.5°C to 69.4 °C – ΑΣΦΑ Part B Submit Previous Answers Request Answer X Incorrect; Try Again ▼ to heat 6.15 g of water from 5.5°C to 69.4 °C - ΑΣΦ 3 Part C ID ΑΣΦ Submit ▼ Part D lost when 75.6 g of water cools from 86.4° C to 3.6 °C |Ε| ΑΣΦ Part E Request Answer to heat 12.2 g of silver from 112° C to 295 °C lost when 75.6 g of water cools from 86.4° C to 3.6 °C ID ΑΣΦ Submit Part F ? Request Answer to heat 12.2 g of silver from 112° C to 295 °C ? IVE ΑΣΦ ? J ? ? ? J cal J cal
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
Question
Please answer parts A, B, C, D, E, F, G and H.
Transcribed Image Text:Use the heat equation to calculate the energy, in joules
and calories, for each of the following (see the table):
cal/g °C
J/g °C
Substance
Elements
Aluminum, Al(s)
Copper, Cu(s)
Gold, Au(s)
Iron, Fe(s)
Silver, Ag(s)
Titanium, Ti(s)
Compounds
Ammonia, NH₂(g)
Ethanol, C₂H₂OH(1)
Sodium chloride, NaCl(s)
Water, H₂O(!)
Water, H₂O(s)
Silver, Ag(s)
Titanium, Ti(s)
Compounds
Ammonia, NH₂(g)
Ethanol, C₂H₂OH(1)
Sodium chloride, NaCl(s)
Water, H₂O(1)
Water, H₂O(s)
0.214
0.897
0.0920
0.385
0.0308 0.129
0.108
0.452
0.0562
0.235
0.125
0.523
Use the heat equation to calculate the energy, in joules
and calories, for each of the following (see the table):
Substance
cal/g °C J/g °C
Elements
Aluminum, Al(s)
Copper, Cu(s)
Gold, Au(s)
Iron, Fe(s)
0.488
0.588
0.207
1.00
0.485
Substance
Elements
Aluminum, Al(s)
Copper, Cu(s)
Gold, Au(s)
Iron, Fe(s)
Silver, Ag(s)
Titanium, Ti(s)
Compounds
Ammonia, NH3(g)
Ethanol, C₂H₂OH(1)
Sodium chloride, NaCl(s)
Water, H₂O(1)
Water, H₂O(s)
2.04
2.46
0.864
4.184
2.03
0.214
0.897
0.0920
0.385
0.0308 0.129
0.108 0.452
0.0562
0.125
0.488
0.588
0.207
1.00
0.485
0.235
0.523
2.04
2.46
0.864
4.184
2.03
Use the heat equation to calculate the energy, in joules
and calories, for each of the following (see the table):
cal/g °C J/g °C
0.214
0.897
0.0920 0.385
0.0308 0.129
0.108 0.452
0.0562 0.235
0.125
0.523
0.488
2.04
0.588 2.46
0,207
0.864
1.00
4.184
0.485
2.03
Part A
to heat 6.15 g of water from 5.5°C to 69.4 °C
Π ΑΣΦ 6
Submit Previous Answers Request Answer
X Incorrect; Try Again
Part B
to heat 6.15 g of water from 5.5°C to 69.4 °C
Π| ΑΣΦ →
Part C
ΨΠ᾿ ΑΣΦ
Submit
lost when 75.6 g of water cools from 86.4° C to 3.6 °C
Part D
Part E
ΠΙ ΑΣΦ 3
Request Answer
3
to heat 12.2 g of silver from 112° C to 295 °C
IVE ΑΣΦ
Submit
lost when 75.6 g of water cools from 86.4° C to 3.6 °C
Part F
?
Request Answer
to heat 12.2 g of silver from 112° C to 295 °C
IVE ΑΣΦ
?
?
J
?
?
?
J
cal
J
cal
ole
Je
Transcribed Image Text:Use the heat equation to calculate the energy, in joules
and calories, for each of the following (see the table):
cal/g °C
J/g °C
Substance
Elements
Aluminum, Al(s)
Copper, Cu(s)
Gold, Au(s)
Iron, Fe(s)
Silver, Ag(s)
Titanium, Ti(s)
Compounds
Ammonia, NH3(g)
Ethanol, C₂H₂OH(1)
Sodium chloride, NaCl(s)
Water, H₂O(!)
Water, H₂O(s)
0.214
0.897
0.0920 0.385
0.0308
0.129
0.108
0.452
0.0562 0.235
0.125
0.523
0.488
0.588
0.207
1.00
0.485
2.04
2.46
0.864
4.184
2.03
Part G
lost when 16.1 g of gold cools from 224°C to 131 °C
17 ΑΣΦ
Part H
?
lost when 16.1 g of gold cools from 224°C to 131 °C
15. ΑΣΦ
?
J
cal
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