A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. :0: :O-H 个回 A) The arrow points at the proton that is electron deficient. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. B) The arrow points at the proton that is electron rich. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow fro+ the base (HO) to the proton showing the formation of a new bond. The second arrow
A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. :0: :O-H 个回 A) The arrow points at the proton that is electron deficient. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. B) The arrow points at the proton that is electron rich. The hydroxide ion is electron deficient due to the difference in the electronegativity between the oxygen and the hydrogen atoms. The arrow indicates that the electron rich hydrogen of the carboxylic acid (RC(=O)-O-H) moves to the oxygen of the hydroxide ion to form water. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole that leaves the hydrogen with a low electron density. The electrons follow the arrow fro+ the base (HO) to the proton showing the formation of a new bond. The second arrow
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Electronic Effects
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Drawing Resonance Forms
In organic chemistry, resonance may be a mental exercise that illustrates the delocalization of electrons inside molecules within the valence bond theory of octet bonding. It entails creating several Lewis structures that, when combined, reflect the molecule's entire electronic structure. One Lewis diagram cannot explain the bonding (lone pair, double bond, octet) elaborately. A hybrid describes a combination of possible resonance structures that represents the entire delocalization of electrons within the molecule.
Using Molecular Structure To Predict Equilibrium
Equilibrium does not always imply an equal presence of reactants and products. This signifies that the reaction reaches a point when reactant and product quantities remain constant as the rate of forward and backward reaction is the same. Molecular structures of various compounds can help in predicting equilibrium.
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electronegativity between the oxygen and the
hydrogen atoms. The arrow indicates that the
electron rich hydrogen of the carboxylic acid
(RC(=O)-O-H) moves to the oxygen of the
hydroxide ion to form water.
C) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole that
leaves the hydrogen with a low electron
density. The electrons follow the arrow from
the base (HO) to the proton showing the
formation of a new bond. The second arrow
indicates the electrons from the O-H bond
moving to the oxygen of the carboxylic acid
breaking the O-H bond.
Home
D) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole that
leaves the hydrogen with a high electron
density. The electrons follow the arrow from
the base (HO) to the proton showing the
formation of a new bond. The second arrow
indicates the electrons from the O-H bond
moving to the oxygen of the carboxylic aci +
breaking the O-H bond.
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Question 4 of 21
A curved arrow mechanism for a Bronsted acid-base reaction is shown below.
Choose the best explanation for this proposed curved arrow mechanism.
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A) The arrow points at the proton that is
electron deficient. The hydroxide ion is
electron deficient due to the difference in the
electronegativity between the oxygen and the
hydrogen atoms. The arrow indicates that the
electron rich hydrogen of the carboxylic acid
(RC(=O)-O-H) moves to the oxygen of the
hydroxide ion to form water.
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B) The arrow points at the proton that is
electron rich. The hydroxide ion is electron
deficient due to the difference in the
electronegativity between the oxygen and the
hydrogen atoms. The arrow indicates that the
electron rich hydrogen of the carboxylic acid
(RC(=O)-O-H) moves to the oxygen of the
hydroxide ion to form water.
C) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole that
leaves the hydrogen with a low electron
density. The electrons follow the arrow fro +
the base (HO) to the proton showing the
formation of a new bond. The second arrow
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