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I want you to solve for HAc using the ammonia sample as reference.

I want you to solve for HAc using the ammonia sample as reference.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I want you to solve for HAc using the ammonia sample as reference.
10 -2 K = M MBE [NH,]+[N H₂ ] INH, HÌNH NH, tHeo= Nhĩ CH + + [NH₂+ ] [OH-] [NH₂] xw = [H" ] [OH"] = 10 th CBF ammonia =BE = [NH₂"] + [A²] = [H ² ] >> (Tou"}]>> [s] => [XH," ] = [OH". because the solitions is basic [NH. an ² 2 1.8x10-5 [MH] 2 + + be 1.8 × 10 14 = C₁ = 10² M 0 4.2x10 1.8 x 10 + Гинит K₁ = 1.8 × 10-3 4 -5 INH [{um, ] [MUN] 1.8×10 5 = K₂ C = O -2 10"" [NH₂²] = 10² = 0 -1- 8 x 10²5 + √(1-8 4160²³) + 4 (1) (10²²) V 2 2.4 x 10-1 = 1.8×105 9.610 -4 = 4.2 X 10² [OH-] >> [#²] M
Transcribed Image Text:10 -2 K = M MBE [NH,]+[N H₂ ] INH, HÌNH NH, tHeo= Nhĩ CH + + [NH₂+ ] [OH-] [NH₂] xw = [H" ] [OH"] = 10 th CBF ammonia =BE = [NH₂"] + [A²] = [H ² ] >> (Tou"}]>> [s] => [XH," ] = [OH". because the solitions is basic [NH. an ² 2 1.8x10-5 [MH] 2 + + be 1.8 × 10 14 = C₁ = 10² M 0 4.2x10 1.8 x 10 + Гинит K₁ = 1.8 × 10-3 4 -5 INH [{um, ] [MUN] 1.8×10 5 = K₂ C = O -2 10"" [NH₂²] = 10² = 0 -1- 8 x 10²5 + √(1-8 4160²³) + 4 (1) (10²²) V 2 2.4 x 10-1 = 1.8×105 9.610 -4 = 4.2 X 10² [OH-] >> [#²] M
the МВЕ СВЕ Ka = кис 10-2 Water calculate the and рн Стил H HAC S [H+], Гонт] [нас [++][Ac] [HAC Нас HAC H+ AC²² нас - ІНТІ » LOHI + [н'] = [он] [аст S Cone. тгонт 3 + [HAC] [AC], _H₂0 H2O Ас Ac] 1.8 х10 -5 Кa 3 1.8 x 165 -5 of о ед Spocies in 10 М / 09
Transcribed Image Text:the МВЕ СВЕ Ka = кис 10-2 Water calculate the and рн Стил H HAC S [H+], Гонт] [нас [++][Ac] [HAC Нас HAC H+ AC²² нас - ІНТІ » LOHI + [н'] = [он] [аст S Cone. тгонт 3 + [HAC] [AC], _H₂0 H2O Ас Ac] 1.8 х10 -5 Кa 3 1.8 x 165 -5 of о ед Spocies in 10 М / 09
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